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AnnyKZ [126]
3 years ago
12

A 500-kilogram sports car accelerates uniformly from rest, reaching a speed of 30 meters per second in 6 seconds. During the 6 s

econds, the car has traveled a distance of:_______
(A) 15 m
(B) 30 m
(C) 60 m
(D) 90 m
(E) 180 m
Physics
1 answer:
AlekseyPX3 years ago
4 0

Answer:

90 m

Explanation:

Given that

Mass of the car, m = 500 kg

Initial speed of the car, u = 0 m/s

Final speed of the car, v = 30 m/s

Time taken to travel, t = 6 s

average speed v = (30 + 0) / 2 = 15

We are going to be using the most very basic equations to solve this.

speed can be defined as the ratio of distance with respect to time.

v = d/t, Where

v = speed.

d = distance travelled and

t = time taken

if we invert this, we can get that

d = v.t

distance is multiplication of speed and time. We will be using the average speed we calculated above, so

Distance travelled in 6 s,

d = 15 * 6

d = 90 m.

therefore, the distance travelled by the car in this 6 s is 90 m

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Answer:

W = 16875 J

Explanation:

We have,

Mass of a motorcycle together with its rider is 150 kg

It is required to find the work is needed to set its movement at 15 metre per second. The work done is given by :

W=\dfrac{1}{2}mv^2

Plugging all the values in above formula such that :

W=\dfrac{1}{2}\times 150\times (15)^2\\\\W=16875\ J

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