I WILL GIVE BRAINLIST!! The perimeter of ABCD is 140. Solve for x, y, and z
2 answers:
Answer:
x=10
y = 21°
z=8°
Step-by-step explanation:
we have
AB = AD, CB = CD,
AC perpendicular to DB, AC is angle bisector of DAB and DCB
Perimeter = 140
2(2x + 7 + 4x +3) = 140
6x + 10 = 70
6x = 60
x = 60/6=10
x=10
again
3y - 1 +28° =90
3y - 1 = 90° - 28°
3y - 1 = 62°
3y = 63°
y = 21°
again
4z+58°=90
4z = 90° - 58
4z = 32°
z=32/4
z=8°
Answer:
<u>Properties:</u>
AB = AD, CB = CD, AC⊥DB, AC is angle bisector of DAB and DCB <u>Find x:</u>
P = 140 2(2x + 7 + 4x +3) = 140 6x + 10 = 70 6x = 60 x = 10 <u>Find y:</u>
3y - 1 and 28° are complementary 3y - 1 = 90° - 28° 3y - 1 = 62° 3y = 63° y = 21° <u>Find z:</u>
4z and 58° are complementary 4z = 90° - 58 4z = 32° z = 8°
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