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insens350 [35]
3 years ago
12

A single fair die is rolled. What if event A stays the same, i.e., A={2,4} but B={2,4,5}. Event A is independent with event B. T

rue or False?
Mathematics
1 answer:
den301095 [7]3 years ago
5 0

Answer:

False.

Event A and event B are not independent.

Step-by-step explanation:

We know that event A and event B are

A= {2,4} and B= {2,4,5}.

If the following condition satisfies then event A and event B are independent:

P( A and B)= P(A)*P(B).

Now A and B=?

A and B=A∩B= {2,4} ∩ {2,4,5}

A and B=A∩B={2,4}

The single fair die results in 6 outcomes so, the sample space will contain 6 elements.

Thus,

P(A∩B)=2/6=1/3

P(A)=2/6=1/3

P(B)=3/6=1/2

P(A)*P(B)=1/3*1/2=1/6

As,

P(A∩B)≠P(A)*P(B)

1/3≠1/6

Thus, events A and event B are dependent.

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If one three-digit number ( 0 cannot be a left digit) is chosen at random from all those that can be made from the following set
Oksana_A [137]

The probability of choosing a number that is not a multiple of 2 is P = 0.44

<h3 /><h3>How to find the probability?</h3>

We need to count the number of options for each digit.

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  • For the third digit, we have 9 options {0 ,1, 2, 3, 4, 5, 6, 7, 8}.

The total number of combinations is the product between the numbers of options:

C = 8*9*9 = 648

If we want our number to not be a multiple of 2 then it must end in a odd digit, the combinations that meet that condition are:

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C = 8*9*4 = 288

Then the probability of selecting a 3 digit number that is not a multiple of 2 is:

P = 288/648 = 0.44

If you want to learn more about probability, you can read:

brainly.com/question/251701

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Step-by-step explanation:  and explain

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