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Finger [1]
3 years ago
15

If the average (arithmetic mean) of 2, 7, and x is 12, what is the value of x?

Mathematics
1 answer:
posledela3 years ago
5 0

Answer:

27. (2+7+27=36 36÷3=12) 36=total of the three numbers, 3=Amount of numbers, 12=Average

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the answer is 40/100 × 20

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3 years ago
Describe the steps you would use to factor 2x3 + 5x2 – 8x – 20 completely. Then state the factored form.
WARRIOR [948]
The polynomial 2x^3 + 5x^2-8x-20 may have solutions which are the divisors of -20, therefore -20 has the following divisors: \pm 1, \pm 2, \pm 4, \pm 5, \pm 10, \pm 20.
If x=1, then 2\cdot1^3 + 5\cdot1^2-8\cdot1-20=-20\neq 0,
if x=-1, then 2\cdot(-1)^3 + 5\cdot(-1)^2-8\cdot(-1)-20=-9\neq 0,
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5 0
3 years ago
Read 2 more answers
The area of a triangle is 24 square inches. What is the height of the triangle if the base length is 6 inches?
evablogger [386]

I think that it would be 8 inches because to find the area of a triangle is base times height divided by two. So I just doubled the area and divided by 6.

I'm sorry if this is incorrect!

6 0
3 years ago
A statue is mounted on top of a 21 foot hill. From the base of the hill to where you are standing is 57feet and the statue subte
AleksandrR [38]

Please find the attached diagram for a better understanding of the question.

As we can see from the diagram,

RQ = 21 feet = height of the hill

PQ = 57 feet = Distance between you and the base of the hill

SR= h=height of the statue

\angle SPR=Angle subtended by the statue to where you are standing.

\angle x=\angle RPQ= which is unknown.

Let us begin solving now. The first step is to find the angle \angle x which can be found by using the following trigonometric ratio in \Delta PQR :

tan(x)=\frac{RQ}{PQ} =\frac{21}{57}

Which gives \angle x to be:

\angle x=tan^{-1}(\frac{21}{57})\approx20.22^{0}

Now, we know that\angle x and \angle SPR can be added to give us the complete angle \angle SPQ in the right triangle \Delta SPQ.

We can again use the tan trigonometric ratio in \Delta SPQ to solve for the height of the statue, h.

This can be done as:

tan(\angle SPQ)=\frac{SQ}{PQ}

tan(7.1^0+20.22^0)=\frac{SR+RQ}{PQ}

tan(27.32^0)=\frac{h+21}{57}

\therefore h+21=57tan(27.32^0)

h\approx8.45 ft

Thus, the height of the statue is approximately, 8.45 feet.

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3 years ago
Help please Algebra 1 <br> Simplify 4y-6yx+y
astraxan [27]
I hope you will like my answer

5 0
3 years ago
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