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Finger [1]
3 years ago
15

If the average (arithmetic mean) of 2, 7, and x is 12, what is the value of x?

Mathematics
1 answer:
posledela3 years ago
5 0

Answer:

27. (2+7+27=36 36÷3=12) 36=total of the three numbers, 3=Amount of numbers, 12=Average

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Subtract the given function and indicate the domain of the difference
maxonik [38]

Answer:

The domain is x\in (-\infty,\infty).

Step-by-step explanation:

Given functions f(x)=x^2+3x+1 and g(x)=2x^2-4x-1

Subtract these two functions:

f(x)-g(x)\\ \\=(x^2+3x+1)-(2x^2-4x-1)\\ \\=x^2+3x+1-2x^2+4x+1\\ \\=(x^2-2x^2)+(3x+4x)+(1+1)\\ \\=-x^2+7x+2

Plot these difference on the coordinate plane (see attached diagram). This function is defined for all vlues of x, so the domain is x\in (-\infty,\infty).

6 0
3 years ago
Dana needs 4.25 cups of flour to make 5 dozen cookies. How
Ne4ueva [31]

Answer:

C. 0.85 cups

Step-by-step explanation:

4.25/5 = 0.85

5 0
3 years ago
3) Write the inequality that
masha68 [24]

Answer:

  • See below

Step-by-step explanation:

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<u>So the inequality for this case is:</u>

  • - 26.00 > - 147.00
3 0
2 years ago
Given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle
Anastasy [175]

Answer:

Part 1) False

Part 2) False

Step-by-step explanation:

we know that

The equation of the circle in standard form is equal to

(x-h)^{2} +(y-k)^{2}=r^{2}

where

(h,k) is the center and r is the radius

In this problem the distance between the center and a point on the circle is equal to the radius

The formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

Part 1) given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

(x+3)^{2} +(y-4)^{2}=r^{2}

Find the distance (radius) between the center (-3,4) and (-6,2)

substitute in the formula of distance

r=\sqrt{(2-4)^{2}+(-6+3)^{2}}

r=\sqrt{(-2)^{2}+(-3)^{2}}

r=\sqrt{13}\ units

The equation of the circle is equal to

(x+3)^{2} +(y-4)^{2}=(\sqrt{13}){2}

(x+3)^{2} +(y-4)^{2}=13

Verify if the point (10,4) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=10,y=4

substitute

(10+3)^{2} +(4-4)^{2}=13

(13)^{2} +(0)^{2}=13

169=13 -----> is not true

therefore

The point is not on the circle

The statement is false

Part 2) given the center of the circle (1,3) and a point on the circle (2,6), (11,5) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

(x-1)^{2} +(y-3)^{2}=r^{2}

Find the distance (radius) between the center (1,3) and (2,6)

substitute in the formula of distance

r=\sqrt{(6-3)^{2}+(2-1)^{2}}

r=\sqrt{(3)^{2}+(1)^{2}}

r=\sqrt{10}\ units

The equation of the circle is equal to

(x-1)^{2} +(y-3)^{2}=(\sqrt{10}){2}

(x-1)^{2} +(y-3)^{2}=10

Verify if the point (11,5) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=11,y=5

substitute

(11-1)^{2} +(5-3)^{2}=10

(10)^{2} +(2)^{2}=10

104=10 -----> is not true

therefore

The point is not on the circle

The statement is false

7 0
3 years ago
Find the length of a diagonal<br> of a square with sides of 14<br> feet long.<br> [?][feet<br> /
inessss [21]

Answer:

14√2 feet

Step-by-step explanation:

The length of a diagonal of a square is L=S\sqrt{2} where S is the side length of the square. Therefore, L=14\sqrt{2}.

4 0
2 years ago
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