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Mashutka [201]
3 years ago
8

Please help me i need this answer asap ​

Mathematics
1 answer:
olasank [31]3 years ago
7 0
It’s 69 for sure dude hope this helps
Not takashi
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How much simple interest is earned on an investment of 1,250 if the money is invested for 5 years at an annual interest rate of
Alekssandra [29.7K]
<h3>Answer:  $281.25</h3>

Work Shown:

i = P*r*t

i = 1250*0.045*5

i = 281.25

8 0
2 years ago
These are the means and standard deviations for samples of heights from two kinds of trees. Tree A = Mean: 25ft = standard devia
tatuchka [14]

Answer:

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3 years ago
WILL MARK BRAINIEST IF CORRECT.
bonufazy [111]

Answer:

1, 2, 5 and 6 are the answers.

Step-by-step explanation:

2 is correct because the arrow shows that the number line continues till infinity. 5 is correct because any fraction is possible as no restriction of integer value is placed. Any number less than 7 is not included. There are some confusions with 1 as it's not a solid color, So, I assume -7 is not included.

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4 years ago
Complete the point-slope equation of the line through ( − 5 , 4 ) (−5,4)left parenthesis, minus, 5, comma, 4, right parenthesis
Tanzania [10]

The point slope form of equation through given points is:

y-6=\frac{1}{3}(x-1)

Step-by-step explanation:

Given points are:

(x1,y1) = (-5,4)

(x2,y2) = ((1,6)

First of all we have to find the slope of line

So,

m=\frac{y_2-y_1}{x_2-x_1}\\=\frac{6-4}{1+5}\\=\frac{2}{6}\\=\frac{1}{3}

Point-slope form is given by:

y-y_1=m(x-x_1)

Putting m=1/3

y-y_1=\frac{1}{3}(x-x_1)

Putting (1,6) in the equation

y-6=\frac{1}{3}(x-1)

The point slope form of equation through given points is:

y-6=\frac{1}{3}(x-1)

Keywords: Point slope form

Learn more about point slope form at:

  • brainly.com/question/2150928
  • brainly.com/question/2154850

#LearnwithBrainly

3 0
3 years ago
1. what is the exact demical value of 225/16?<br> 2. what is the exact decimal value of 77/12?
SOVA2 [1]

Answer:

14.0625 = \frac{225}{16}

6.41666666666... = \frac{77}{12}

Hope that this helps!

7 0
3 years ago
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