The angular frequency of the cyclotron is 0.07 x Hz.
<h3>What is angular frequency?</h3>
- Angular frequency, abbreviated "ω" is a scalar measure of rotation rate in physics.
- It describes the rate of change of the argument of the sine function, the rate of change of the phase of a sinusoidal waveform, or the angular displacement per unit of time.
<h3>What is cyclotron?</h3>
The cyclotron device is made to accelerate charge particles to extremely high speeds by applying crossed electric and magnetic fields.
<h3>Calculation of angular frequency:</h3>
Given,
B = 0.47 T
r = 0.68
mass of proton = 1.6x
q = 1.6 x
so, the frequency is:
f = qB/2m
f = 1.6 x x 0.47/2x3.14x1.6x
f = 0.07 x
Hence, the angular frequency of the cyclotron is 0.07 x Hz.
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Answer:
1 m
Explanation:
Given that
Mass of the child, m = 15 kg
Distance of the pivot, d = 1.5 m
Force applied, F = 220 N
To solve this problem, we first need to find the torque around the pivot.
Torque, t = mgd, where
m is the mass of the child
g is the acceleration due to gravity and
d is the distance of the pivot.
Thus, we can say that the torque is
T = 15 * 9.8 * 1.5
T = 220.5 Nm
This torque we have gotten would be used to find the distance, using the inverse of the equation.
T = F * d
d = T / F
d = 220.5 / 220
d = 1 m
Therefore, the minimum distance on the other side of the pivot required is 1 m
Explanation:
the unknown resistance is 9ohm