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Dmitriy789 [7]
3 years ago
13

Gravity: The force due to gravity is F=mg where g=9.80 m/s². A. Find the force due to gravity on a 41.63-kg object. B. The force

due to gravity on an object is 632 kg•m/s². What is the mass?
Physics
1 answer:
olga_2 [115]3 years ago
4 0
A. F=mg
= 41.63kg x 9.8m/s²
= 407.974
= 408N (3 significant figure)
B. F=mg
632N= y x 9.8m/s²
y= 632 ÷ 9.8
y = 64.48
y= 64.5kg (3 significant figure)
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Explanation:

The speed of a wave is given by :

v=f\lambda ......(1)

(i) Here, the wavelength of a sound wave in air reduces by a factor of 3. Equation (1) becomes :

\lambda=\dfrac{v}{f}

Wavelength and frequency are inversely proportional to each other. So, if wavelength of a sound wave in air reduces by a factor of 3, then the frequency will increases by a factor of 3.

(ii) It remains the same.

8 0
3 years ago
Suppose that you'd like to find out if a distant star is moving relative to the earth. The star is much too far away to detect a
rjkz [21]

Answer:

The speed will be "18km/s". A further explanation is given below.

Explanation:

According to the question, the values are:

Wavelength,

\lambda = 656.46 \ nm

\Delta \lambda = 0.04

c=3\times 10^8

As we know,

⇒  \frac{\Delta \lambda}{\lambda} =\frac{v}{c}

On substituting the values, we get

⇒  \frac{656.46}{0.04} =\frac{v}{3\times 10^8}

⇒         v=\frac{656.46}{0.04} (3\times 10^8)

⇒            =16411.5\times 3\times 10^8

⇒            =18280 \ m/s

or,

⇒            =18 \ km/s

8 0
2 years ago
A force of 100 N acts on a body and moves at a distance of 2 m in the direction of the force. How much work has been done?
Flauer [41]

Answer:

200 joules

Explanation:

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5 0
2 years ago
Se lanza una pelota de béisbol desde la azotea de un edificio de 25 m de altura con velocidad inicial de magnitud 10 m/s y dirig
MissTica

Answer:

 v_f = 24.3 m / s

Explanation:

A) In this exercise there is no friction so energy is conserved.

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         Em₀ = K + U = ½ m v₀² + m g y₀

Final point. On the floor

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         Emo = Em_g

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        v_f² = v₀² + 2 g y₀

         

let's calculate

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6 0
3 years ago
In the graph, which region shows nonuniform positive acceleration?
cricket20 [7]

Answer: A.AB

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As we can see in the attached image, the graph can be divided in four segments:

OA: In this segment the acceleration is changing at a uniform rate. In addition we can see it has a positive slope, hence we are dealing with a positive uniform acceleration.

AB: In this segment the acceleration is changing at a nonuniform rate, since  in this part it is not possible to calculate the slope. However if this were uniform, the slope woul be positive. This means the <u>acceleration is nonuniform and positive.</u>

BC: In this segment the acceleration is changing at a nonuniform rate, since  in this part it is not possible to calculate the slope. However if this were uniform, the slope woul be negative. This means the acceleration is nonuniform and negative.

CD: In this segment the acceleration is changing at a uniform rate. In addition we can see it has a negative slope, hence we are dealing with a negative uniform acceleration.

From all these segments, the only one that fulfils the nonuniform positive acceleration condition is option A:

Segment AB

3 0
2 years ago
Read 2 more answers
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