The potential energy will be 1.46*10^-4J.
To find the answer, we have to know about the torque acting on a current loop in a uniform magnetic field.
<h3>How to find the potential energy of the loop?</h3>
- We have the expression for torque acting on a current loop in a uniform magnetic field as,
where; M is the magnetic dipole moment, B is the magnetic field , and theta is the angle between M and B.
- As we know that, the torque is equal to force times the perpendicular distance. Thus, it is equivalent to the work done. This work is stored as the potential energy in the loop.
- Thus, the potential energy will be,
Thus, we can conclude that, the potential energy will be 1.46*10^-4J.
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From the calculations, the value of the acceleration due to gravity is 0.38 m/s^2.
<h3>What is weight?</h3>
The weight of an object is obtained as the product of the mass of the body and the acceleration due to gravity.
Thus;
When;
mass = 120 kg
weight = 46 N
acceleration due to gravity = 46 N/120 kg
=0.38 m/s^2
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The magnetizing current in a transformer is rich in 3rd harmonic. This is because harmonics are AC voltages and currents with frequencies that are generally higher.
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