Answer:
Explanation:
Initial momentum is 1.5e6(3) = 4.5e6 kg•m/s
An impulse results in a change of momentum
The tug applied impulse is 12000(10) = 120000 N•s or 0.12e6 kg•m/s
The remaining momentum is 4.5e6 - 0.12e6 = 4.38e6 kg•m/s
The barge velocity is now 4.38e6 / 1.5e6 = 2.92 m/s
The tug applies 0.012e6 N•s of impulse each second.
The initial barge momentum will be zero in
t = 4.5e6 / 0.012e6 = 375 s or 6 minutes and 15 seconds
To stop the barge in one minute(60 s), the tug would have to apply
4.5e6 / 60 = 75000 N•s /s or 75 000 N
Answer:
I really hope this is right I think this is Diffuse I'm sorry if its worng
Given :
Initial velocity, u = -15 m/s.
Acceleration , a = 2 m/s².
Time taken to applied brake, t = 2.5 s.
To Find :
The velocity of the car at the end of the braking period.
How far has the car moved during the braking period.
Solution :
By equation :
Now, distance covered by car is :
Hence, this is the required solution.
Answer:
a)
b)
c) ΔK=
d)ΔK=
Explanation:
From the exercise we know that there is a collision of a sports car and a truck.
So, the sport car is going to be our object number 1 and the truck object number 2.
Since the two vehicles remain locked together after the collision the final mass is:
a) To find the velocity of the two vehicles just after the collision we must use linear's momentum principle
b) To find the speed the truck should have had so both vehicles stopped in the collision we need to use the same principle used before
c) To find the change in kinetic energy we need to do the following steps:
ΔK=
ΔK=
d) The change in kinetic energy where the two vehicles stopped in the collision is:
ΔK=
ΔK=
Hi there!
1.
The period of a pendulum can be calculated using the following equation:
T = period (s)
L = length of string (m)
g = acceleration due to gravity (m/s²)
Plug in the values:
2.
Calculate the period:
Frequency is the reciprocal of the period, so: