Answer:
56 groups of 5 Fabergé eggs can be taken.
Step-by-step explanation:
It is given that Ashley is packing her bags for her vacation. She has 8 unique Fabergé eggs, but only 5 fit in her bag. In order to find how many different groups of 5 Faberge' eggs can she take, we apply the combination formula:
![8C_{5}=\frac{8!}{5!(8-5)!}](https://tex.z-dn.net/?f=8C_%7B5%7D%3D%5Cfrac%7B8%21%7D%7B5%21%288-5%29%21%7D)
![8C_{5}=\frac{8!}{5!3!}](https://tex.z-dn.net/?f=8C_%7B5%7D%3D%5Cfrac%7B8%21%7D%7B5%213%21%7D)
![8C_{5}=\frac{8{\times}7{\times}6{\times}5!}{5!{\times}3{\times}2}](https://tex.z-dn.net/?f=8C_%7B5%7D%3D%5Cfrac%7B8%7B%5Ctimes%7D7%7B%5Ctimes%7D6%7B%5Ctimes%7D5%21%7D%7B5%21%7B%5Ctimes%7D3%7B%5Ctimes%7D2%7D)
![8C_{5}=56](https://tex.z-dn.net/?f=8C_%7B5%7D%3D56)
Thus, 56 groups of 5 Fabergé eggs can be taken.
Answer: ![\dfrac14](https://tex.z-dn.net/?f=%5Cdfrac14)
Step-by-step explanation:
Given: The factory produces equal quantities of four flavors cherry lemon orange and strawberry.
Let orange candy= cherry = lemon = strawberry = x
Total candies = x + x + x + x= 4x
The probability that a randomly selected candy is orange = ![\dfrac{x}{4x}=\dfrac14](https://tex.z-dn.net/?f=%5Cdfrac%7Bx%7D%7B4x%7D%3D%5Cdfrac14)
Hence, the probability that a randomly selected candy is orange = ![\dfrac14](https://tex.z-dn.net/?f=%5Cdfrac14)
Add 1
0.7+1=1.7
1.7+1= 2.7
etc., etc.
Answer:
C
Step-by-step explanation:
Answer:
2(x) +4 = 6
2(x) +4 -4 = 6 - 4
2x = 2
2x/2 = 2/2
x = 1
Step-by-step explanation: