Answer:
2 vertical asymptotes occurring at x = 5 and x = -1
Step-by-step explanation:
given
recall that asymptotic occur at the locations that will make the equation undefined. In this case, the asymptote will occur at x-locations which will cause the denominator to become zero (and hence undefined)
Equating the denominator to zero,
(x-5)(x+1) = 0
(x-5) =0
x = 5 (first asymptote)
or (x+1) = 0
x = -1 (2nd asymptote)
0.6n = n + 31.8
0.6n - n = 31.8
-0.4n = 31.8
n = 31.8 / -0.4
n = -79.5
We want to find the value of cot(θ) given that sin(θ) = 3/8 and θ is an angle in a right triangle, we will get:
cot(θ) = (√55)/3
So we know that θ is an acute angle in a right triangle, and we get:
sin(θ) = 3/8
Remember that:
- sin(θ) = (opposite cathetus)/(hypotenuse)
- hypotenuse = √( (opposite cathetus)^2 + (adjacent cathetus)^2)
Then we have:
opposite cathetus = 3
hypotenuse = 8 = √(3^2 + (adjacent cathetus)^2)
Now we can solve this for the adjacent cathetus, so we get:
adjacent cathetus = √(8^2 - 3^2) = √55
And we know that:
cot(θ) = (adjacent cathetus)/(opposite cathetus)
Then we get:
cot(θ) = (√55)/3
If you want to learn more, you can read:
brainly.com/question/15345177
The answer to your problem is x=26
