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erastovalidia [21]
2 years ago
15

PLEASE HELP THIS IS FOR SCIENCE!!!!

Physics
1 answer:
Oksana_A [137]2 years ago
8 0

Answer:

xd vchrfdjtrytft5fttydi765ri756ir56ri75ri75f7tf6tykf5rf65ty gfgcjg

Explanation:

fgjcfrcfjcv mghkckgktygftgvkytfyfvky

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A 730-keV gamma ray Compton-scatters from an electron. Find the energy of the photon scattered at 120°, the kinetic energy of th
romanna [79]

Answer:

Energy of scattered photon is 232.27 keV.

Kinetic energy of recoil electron is 497.73 keV.

The recoil angle of electron is 13.40°

Explanation:

The energy of scattered photon is given by the relation :

E_{2}=\frac{E_{1} }{1+(\frac{E_{1} }{m_{e}c^{2}  })(1-\cos\theta) }     .....(1)

Here E₁ is the energy of incident photon, E₂ is the energy of scattered photon, m_{e} is mass of electron and θ is scattered angle.

Substitute 730 keV for E₁, 511 keV for m_{e} and 120° for θ in equation (1).  

E_{2}=\frac{730 }{1+(\frac{730 }{511  })(1-\cos120) }

E₂ = 232.27 keV

Kinetic energy of recoil electron is given by the relation :

K.E. = E₁ - E₂ = (730 - 232.27 ) keV = 497.73 keV

The recoil angle of electron is given by :

\cot\phi=(1+\frac{E_{1} }{m_{e}c^{2}  })\tan\frac{\theta}{2}

Substitute the suitable values in above equation.

\cot\phi=(1+\frac{730 }{511  })\tan\frac{120}{2}

\cot\phi=4.20

\phi = 13.40°

8 0
3 years ago
A patient is administered 20 mg of iodine-131. How much of this isotope will remain in the body after 40 days if the half-life f
igor_vitrenko [27]

The formula for half-life is:

A_{final}=A_{initial}(\frac{1}{2})^{\frac{t}{h}}

Where A is the amount of iodine-131 initially and after 40 days, t is time, h is half-life of the isotope.  Let's plug in our values to the equation:

A_{final}=20(\frac{1}{2})^{\frac{40}{8}=0.625g

Therefore, the patient has 0.625 grams of iodine-131 after 40 days.

4 0
3 years ago
A cylinder with a movable piston contains 2.00 gg of helium, HeHe, at room temperature. More helium was added to the cylinder an
NikAS [45]

Answer: 1.8 g

Explanation:

We start first, by calculating the amount of Helium

n = m/M

m = mass of Helium

M = molar mass if Helium

n = 2/4 = 0.5 moles

proceeding further, we use ideal gas law. PV = nRT

Then we have

P1V1/n1T1 = P2V2/n2T2

So that,

n2 = n1T1P2V2/P1V1T2

From the question, we know that, P1 = P2, and T1 = T2. So that,

n2 = n1v2/v1

n2 = (0.5 * 3.9) / 2

n2 = 1.95/2

n2 = 0.975 moles. With this, we can determine the mass, m2 of Helium

n = m/M

m = n * M

m = 0.975 * 3.9

m = 3.8

The difference between both masses are 3.8 - 2 = 1.8 g

Thus, 1.8 g of Helium was added to the cylinder

3 0
3 years ago
Read 2 more answers
What is a scientific theory? A law that is always true a hypothesis about nature and educated guess based on observations an exp
egoroff_w [7]

Answer:

an explanation on how the natural world works

Explanation:

A scientific theory is simply an explanation into how the natural world works. Scientific theory is formulated after a series of hypothesis that has ascertained how true an observation is.

A theory is provides explanation into an observed feature. It can be disproved when new evidences are found. This brings about revision into scientific proofs.

5 0
3 years ago
PLEASE HELP!! <br><br> 6. What amount of force is needed to accelerate a 560kg bus at 1.4m/s??
Keith_Richards [23]

Answer:ugly nlikeieieisj

Explanation:ebebbebebebes

8 0
3 years ago
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