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mojhsa [17]
3 years ago
10

Describe the motion of an object that has an acceleration of 0m/s2

Physics
1 answer:
solong [7]3 years ago
6 0
Zero acceleration means the object's velocity is not changing.
So the object is moving in a straight line, at a constant speed
that could be anything (including zero) as long as it's constant.
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georgia is jogging with a velocity of 4 m/s when she accelerates at 2 m/s squared for 3 seconds. How fast is Georgia running now
yaroslaw [1]
Let v1 be the initial velocity of 4m/s
Let v2 be the final velocity
v2=v1+(3s*2m/s^2) = 4m/s + 6m/s = 10m/s
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3 years ago
¿A que velocidad viaja la luz?
ss7ja [257]
La velocidad que viaja la luz es 299,792 km por hora
7 0
3 years ago
Read 2 more answers
What is the speed of a person that walk 400 meters in 1900 seconds
Nezavi [6.7K]

Answer:

Explanation:

.

6 0
3 years ago
*example included* Two uncharged spheres are separated by 3.50 m. If 1.30 ✕ 10¹² electrons are removed from one sphere and place
likoan [24]

Considering the Coulomb's Law, the magnitude of the Coulomb force is 3.1865 N.

<h3>Coulomb's Law</h3>

Charged bodies experience a force of attraction or repulsion on approach.

From Coulomb's Law it is possible to predict what the electrostatic force of attraction or repulsion between two particles will be according to their electric charge and the distance between them.

From Coulomb's Law, the electric force with which two point charges at rest attract or repel each other is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them:

F=k\frac{Qq}{d^{2} }

where:

  • F is the electrical force of attraction or repulsion. It is measured in Newtons (N).
  • Q and q are the values ​​of the two point charges. They are measured in Coulombs (C).
  • d is the value of the distance that separates them. It is measured in meters (m).
  • K is a constant of proportionality called the Coulomb's law constant. It depends on the medium in which the charges are located. Specifically for vacuum k is approximately 9×10⁹ \frac{Nm^{2} }{C^{2} }.

The force is attractive if the charges are of opposite sign and repulsive if they are of the same sign.

<h3>This case</h3>

In this case, you know that:

  • The two uncharged sphere are separated by the distance of d= 3.50 m
  • The number of electrons are 1.30×10¹².
  • Electrons is elementary charge and charges on both the sphere is same. The value of electron is 1.602×10⁻¹⁹ C. This is, Q=q=1.30×10¹²×1.602×10⁻¹⁹ C= 2.0826×10⁻⁷ C

Replacing in Coulomb's Law:

F=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{(2.0826x10^{-7} C)x(2.0826x10^{-7} C)}{(3.50 m)^{2} }

Solving:

<u><em>F= 3.1865 N</em></u>

Finally, the magnitude of the Coulomb force is 3.1865 N.

Learn more about Coulomb's Law:

brainly.com/question/26892767

#SPJ1

7 0
2 years ago
Identify and sketch all the external forces acting on the chair. Because the chair can be represented as a point particle of mas
Monica [59]

Answer:

y axis normal (N) and the weight (W)

x axis  pplied force (F) and friction force (fr)

Explanation:

If we have a chair on a horizontal surface, the normal (N) and the weight (W) of the body act on the vertical axis.

On the x axis, the applied force (F) acts in the direction of movement and the friction force (fr) in the opposite direction of movement.

In this exercise we assume that the body tends to move to the right, all the forces can be seen in the adjoint

5 0
3 years ago
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