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cestrela7 [59]
2 years ago
10

Coach McGee uses the table to show her team’s current basketball shot average compared to previous years.

Mathematics
2 answers:
Zinaida [17]2 years ago
7 0

Answer: The answer is B, 3.6 < 37/10

beks73 [17]2 years ago
5 0

Answer: I believe that your answer is B.

37/10 is greater than 3.6.

I hope I helped you!

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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
Archy [21]
Each quarter of a set of data is denoted by a quartile:

The 25th percentile makes up the first quartile Q1.
The 50th percentile represents the second quartile Q2.
The 75th percentile is the third quartile, or Q3.
Finding the second quartile, Q2, is simple. It divides an ordered data set into upper and lower half and is the median of any data set.

The median of the bottom half, excluding the value of Q2, makes up the first quartile, or Q1. The median of the upper half, excluding the value of Q2, makes up the third quartile, or Q3.

Sort the values in your data set from lowest to highest.
the median, please. Q2 stands for the second quartile.
Divide the ordered data collection in half at Q2.
The median of the lower half of the data makes up the lower quartile Q1.
The median of the data's upper half represents the upper quartile Q3.
When determining the first and third quartiles, omit the median if the size of the data set is unusual.
The median, if the size of the data collection is even, is the average of the middle two values. Add the two figures together, then divide by two. The value of the median, which divides the data set into lower and higher half, is

How to Find Interquartile Range
The interquartile range IQR is the range in values from the first quartile Q1 to the third quartile Q3. Find the IQR by subtracting Q1 from Q3.

IQR = Q3 - Q1

How to Find the Minimum

The minimum is the smallest value in a sample data set. Ordering a data set from lowest to highest value, x1 ≤ x2 ≤ x3 ≤ ... ≤ xn, the minimum is the smallest value x1. The formula for minimum is:

Min=1=min()=1

How to Find the Maximum

The maximum is the largest value in a sample data set.

Ordering a data set from lowest to highest value, x1 ≤ x2 ≤ x3 ≤ ... ≤ xn, the maximum is the largest value xn. The formula for maximum is:

Max==max()=1

How to Find the Range of a Set of Data

The range of a data set is the difference between the minimum and maximum. To find the range, calculate xn minus x1.

=−1

So to Answer your question


6 0
1 year ago
Mary and Tom were buying a present for their mother for Mother's Day. Mary spent $12 and Tom spent $28. If they want to share th
Tanya [424]

Answer:

mary owes tom $8

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
CAN SOMEONE HELP ME WITH THIS?!?!
Nat2105 [25]
.......................:)
7 0
3 years ago
Read 2 more answers
Shay mal e 8 2/3 cups of snacks mix she puts all the snack mix into plastic bags she puts 1/3 cup of the snack mix in each bag h
AnnyKZ [126]

Answer:

She needs 26 plastic bags.

Step-by-step explanation:

Given:

Amount of cups of snacks mix = 8 2/3

Rewriting 8 2/3 we get,

Amount of snacks mix = \frac{26}{3}

Number of Cups in each bag = \frac{1}{3}

She puts all the snacks mix in plastic bags

We need to find the number of plastic bags required to put all the snacks mix

Let number of plastic bag be x.

hence we can say that Number of Cups in each bag multiplied by number of plastic bag is equal to  Amount of snacks mix.

\frac{1}{3}x=\frac{26}{3}\\\\x= \frac{26\times3}{3\times1} =26

Hence total number of plastic bags she needs is 26.

6 0
3 years ago
Square OABC is drawn on a centimetre grid. O is (0,0) A is (3,0) B is (3,3) C is (0,3) Write down how many invariant points ther
storchak [24]

Answer:

No invariant point

Step-by-step explanation:

Hello!

When we translate a form, in this case a polygon We must observe the direction of the vector. Since our vector is:

\vec{v}=\left ( \begin{matrix}1\\ 3\end{matrix} \right )

1) Let's apply  that translation to this polygon, a square. Check it below:

2) The invariant points are the points that didn't change after the transformation, simply put the points that haven't changed.

Examining the graph, we can see that no, there is not an  invariant point, after the translation. There is no common point that belongs to OABC and O'A'B'C' simultaneously. All points moved.

3 0
2 years ago
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