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3 years ago

Consider this equation: –3x – 5 2x = 6which is an equivalent equation after combining like terms?

Mathematics

1 answer:

Alla [95]3 years ago

7 0

-3x-5+2x=6
2x-3x-5=6
-1x-5=6
-x-5=6
-x=11
x=11
an equivilent equaiton is x=11

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Evaluate <br> 3a^2-5b+8 when a=-2 and b=3

iVinArrow [24]

3 (-2)^2 -5 (3)+8
3 (4)-5 (3)+8
12-15+8
-3+8=5
Hope this helps :)

6 0

3 years ago

Three subtracted by a square of a number

Svetradugi [14.3K]

Answer:

3-x^2

Step-by-step explanation:

Let x be the number

The square is x^2

3 subtract the square of a number

3-x^2

8 0

2 years ago

Refer to the two statements below. Which pair of words will make the statements true? 1) 0 is __ than 4 2) -3 is __ than 4 less

k0ka [10]

Less for statement 1 and less for statement 2

4 0

3 years ago

A sample of 100 cars driving on a freeway during a morning commute was drawn, and the number of occupants in each car was record

makkiz [27]

Answer:

$E(X)=1*0.74 +2*0.1 +3*0.11+ 4*0.03 +5*0.02=1.49$

$Var(X)=E(X^2)-[E(X)]^2 =3.11-(1.49)^2 =0.8899$

$Sd(X)=\sqrt{Var(X)}=\sqrt{0.8899}=0.943$

Step-by-step explanation:

For this case we have the following data given:

X 1 2 3 4 5

F 74 10 11 3 2

The total number of values are 100, so then we can find the empirical probability dividing the frequency by 100 and we got the followin distribution:

X 1 2 3 4 5

P(X) 0.74 0.10 0.11 0.03 0.02

Previous concepts

In statistics and probability analysis, the expected value "is calculated by multiplying each of the possible outcomes by the likelihood each outcome will occur and then summing all of those values".

The variance of a random variable Var(X) is the expected value of the squared deviation from the mean of X, E(X).

And the standard deviation of a random variable X is just the square root of the variance.

Solution to the problem

In order to calculate the expected value we can use the following formula:

$E(X)=\sum_{i=1}^n X_i P(X_i)$

And if we use the values obtained we got:

$E(X)=1*0.74 +2*0.1 +3*0.11+ 4*0.03 +5*0.02=1.49$

In order to find the standard deviation we need to find first the second moment, given by :

$E(X^2)=\sum_{i=1}^n X^2_i P(X_i)$

And using the formula we got:

$E(X^2)=1^2 *0.74 +2^2 *0.1 +3^2 *0.11 +4^2 0.03 +5^2 *0.02=3.11$

Then we can find the variance with the following formula:

$Var(X)=E(X^2)-[E(X)]^2 =3.11-(1.49)^2 =0.8899$

And then the standard deviation would be given by:

$Sd(X)=\sqrt{Var(X)}=\sqrt{0.8899}=0.943$

7 0

2 years ago

Do not know how to solve or work out

ehidna [41]

-3x + 20 > = 8
-3x > = 8 - 20
-3x > = -12
x < = -12/-3
x < = 4

( - infinity, 4] <== interval notation

7 0

3 years ago