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3 years ago

What is v^4-1 simplified

2 answers:

4 0

$\bf \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-------------------------------\\\\
v^4-1\implies v^4-1^4\implies (v^2)^2-(1^2)^2\implies \underline{(v^2-1^2)}(v^2+1^2)
\\\\\\
\underline{(v-1)(v+1)}(v^2+1^2)$

lina2011 [118]3 years ago

3 0

The answer is:
(v-1)(v+1)(v^2+1)

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Step-by-step explanation:

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Answer: (a) $\frac{3\pi}{2}$ (b) (0, -1) (c) A (d) -1

Step-by-step explanation:

a) $\frac{11\pi}{2}$ - $\frac{4\pi}{2}$ = $\frac{7\pi}{2}$ - $\frac{11\pi}{2}$ = $\frac{3\pi}{2}$

b) $\frac{3\pi}{2}$ is on the Unit Circle at (0, -1)

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3 years ago

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Answer:

Step-by-step explanation:

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3 years ago

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(21)

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(22)

Similar to (21)

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(23)

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