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tatiyna
3 years ago
15

What is v^4-1 simplified

Mathematics
2 answers:
serg [7]3 years ago
4 0
\bf \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-------------------------------\\\\
v^4-1\implies v^4-1^4\implies (v^2)^2-(1^2)^2\implies \underline{(v^2-1^2)}(v^2+1^2)
\\\\\\
\underline{(v-1)(v+1)}(v^2+1^2)
lina2011 [118]3 years ago
3 0
The answer is:
(v-1)(v+1)(v^2+1)
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Someone help meeee??? Pleaseeee
s2008m [1.1K]

Answer:37

Step-by-step explanation:

(5x7)+2

35+2

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6 0
3 years ago
Choose the correct simplification of the expression a^7b^8/a^4b^4
Alex787 [66]
The answer is B: a^3b^4<span>

Proof:
Simplify the following:
(a^7 b^8)/(a^4 b^4)

Combine powers. (a^7 b^8)/(a^4 b^4) = a^(7 - 4) b^(8 - 4):
a^(7 - 4) b^(8 - 4)

7 - 4 = 3:
a^3 b^(8 - 4)

8 - 4 = 4:
Answer:  a^3 b^4

PS: I just wish that you put the equation down as it's intended i.e.
a^7b^8/a^4b^4 is not the same as (<span>a^7b^8)/(a^4b^4)</span>
</span>
4 0
3 years ago
Read 2 more answers
A constant force acts on a 30-g object and produces an acceleration of 2 m/s2. Find the force in dynes.
FinnZ [79.3K]

Answer:

Force      F = 60 ×10⁻⁵ N

Step-by-step explanation:

Given that mass of the given object (m)  = 30 grams

Given that the acceleration

                                 a = 2 m/s²

<u><em>Force:-</em></u>

The push or pull on an object with mass that causes it to change its velocity

  • Force can make a body that is rest to move
  • it can accelerate the speed of a moving body

<u><em>Formula for force</em></u>

The formula for force    F = m a

                                      F = 30 × 2

                                     F  = 60 gm/s²

                                   F = 60 ×10⁻⁵ N     (∵ 1 d y n = 1gm² = 10⁻⁵N

6 0
3 years ago
Challenge A family wants to rent a car to go on vacation. Company A charges $75.50 and14¢ per mile. Company B charges $30.50 and
sergiy2304 [10]

Company A charges $75.50 and 14¢ per mile, then for x miles, Company A charges 75.5 + 0.14x dollars

Company B charges $30.50 and 9¢ per mile, then for x miles, Company B charges 30.5 + 0.09x dollars

Subtracting the second equation to the first one,

75.5 + 0.14x

-

30.5 + 0.09x

----------------------

45 + 0.05x

For x miles, Company A charges 45 + 0.05x dollars more than Company B.

6 0
1 year ago
If I have an equation in which x = pounds, and y = total cost, can I substitute quarts into the equation
Colt1911 [192]

Answer:

Yes, you can

Step-by-step explanation:

As a point of reference, assume the equation is:

y = 5x

Where

y = total\ cost

and

x = pounds

In standard unit of conversion:

1\ pound = 0.4793\ quart

So:

x\ pounds = 0.4793x\ quart

Substitute 0.4793x for x in y = 5x

y = 5 * 0.4793x

y = 2.3965x

The above equation is the equivalent of y = 5x in quarts

<em>So, irrespective of what the equation is, you can always substitute quarts into the equation.</em>

8 0
3 years ago
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