Answer:
never heard about it
Step-by-step explanation:
Answer:
first, we put them in order
78,[80],83,(85),86,[87],90
Q1 = 80
Q2 (median) = 85
Q3 = 87
Interquartile range (IQR) = Q3 - Q1 = 87 - 80 = 7 <==
Hope this helps!
This question above is incomplete
Complete Question
Jim had 103 red and blue marbles. After giving 2/5 of his blue marbles and 15 of his red marbles to Samantha, Jim had 3/7 as many red marbles as blue marbles. How many blue marbles did he have originally?
Answer:
70 Blue marbles
Step-by-step explanation:
Let red marbles = R
Blue marbles = B
Step 1
Jim had 103 red and blue marbles.
R + B = 103.......Equation 1
R = 103 - B
Step 2
After giving 2/5 of his blue marbles and 15 of his red marbles to Samantha, Jim had 3/7 as many red marbles as blue marbles
2/5 of B to Samantha
Jim has = B - 2/5B = 3/5B left
He also gave 15 red marbles to Samantha
= R - 15
The ratio of what Jim has left
= Red: Blue
= 3:7
= 3/7
Hence,
R - 15/(3/5)B = 3/7
Cross Multiply
7(R - 15) = 3(3/5B)
7R - 105 = 3(3B/5)
7R - 105 = 9B/5
Cross Multiply
5(7R - 105) = 9B
35R - 525 = 9B............ Equation 2
From Equation 1, we substitute 103 - B for R in Equation 2
35(103 - B) - 525 = 9B
3605 - 35B - 525 = 9B
Collect like terms
3605 - 525 = 9B + 35B
3080 = 44B
B = 3080/44
B = 70
Therefore, Jim originally had 70 Blue marbles.
From the given graph, we can tell kl=lm
therefore,
3x + 2 = 5x - 10
3x+2-2=5x-10-2
subtract 2 from both sides.
3x+ 0 =5x-12
3x=5x-12
3x-5x=5x-5x-12
subtract 5x from both sides.
-2x=0-12
-2x=-12
(-2x)/-2=-12/-2
divide both sides by -2.
1x= 6 -12/-2=6
and of course the -2 and -2 cancel on left side leaving 1x.
x=6
KL = 3x+2 = 20 units