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tatiyna
3 years ago
15

What is v^4-1 simplified

Mathematics
2 answers:
serg [7]3 years ago
4 0
\bf \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-------------------------------\\\\
v^4-1\implies v^4-1^4\implies (v^2)^2-(1^2)^2\implies \underline{(v^2-1^2)}(v^2+1^2)
\\\\\\
\underline{(v-1)(v+1)}(v^2+1^2)
lina2011 [118]3 years ago
3 0
The answer is:
(v-1)(v+1)(v^2+1)
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