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Vadim26 [7]
3 years ago
14

Evaluate when x = 3 -10x = ?

Mathematics
1 answer:
Ber [7]3 years ago
7 0

Answer:

√ 96

log  ∨13  ( 28 )

log  ∨2  ( 16 )

click brainliest and thanks

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Jacqueline's piggy bank contains $6.20 in dimes and quarters. There are 32 coins in all. How many of each kind are there?
Yanka [14]
20 quarters and 2 dimes!! (Take a look at my question if possible!?)
3 0
3 years ago
A line, y = mx + b, passes through the point (10, 3) and is parallel to the line 2x+5y=12.
slava [35]

We have been given that a line y=mx+b passes through the point (10, 3) and is parallel to the line 2x+5y=12. We are asked to find the y-intercept of the line.

First of all we will rewrite our given equation in slope-intercept form as:

2x-2x+5y=12-2x

5y=-2x+12

\frac{5y}{5}=-\frac{2}{5}x+\frac{12}{5}

y=-\frac{2}{5}x+\frac{12}{5}

We know that slope of parallel lines is equal, so slope of parallel line to our given line would be -\frac{2}{5}.

Now we will use slope-intercept form of equation to find y-intercept.

y=mx+b, where,

m = Slope,

b = The y-intercept.

Let us substitute m=-\frac{2}{5} and coordinates of point (10,3) in above equation as:

3=-\frac{2}{5}(10)+b

3=-2(2)+b

3=-4+b

3+4=-4+4+b

7=b

Therefore, the y-intercept is 7 and our required equation would be y=-\frac{2}{5}x+7.

5 0
3 years ago
a tree casts a shadow that is 18 feet in length. If the angle of elevation is 28 degrees, which of the following best represents
pishuonlain [190]
Check the picture below

make sure your calculator is in Degree mode.

3 0
4 years ago
S. At Food Lion, 28 of every 35 jars of peanut butter on the shelves are creamy peanut butter. What percent of the jars of peanu
Alborosie

Answer:

7/35 or 20% of the jars are not creamy

7 0
3 years ago
Read 2 more answers
find the surface area of a right regular hexagonal pyramid with sides 3 cm and slant heights 6cm. show all of your work.​
DedPeter [7]

Answer:

The surface area of right regular hexagonal pyramid = 82.222 cm³

Step-by-step explanation:

Given as , for regular hexagonal pyramid :

The of base side = 3 cm

The slant heights = 6 cm

Now ,

The surface area of right regular hexagonal pyramid = \frac{3\sqrt{3}}{2}\times a^{2} + 3 a \sqrt{h^{2}+ 3\times \frac{a^{2}}{4}}

Where a is the base side

And h is the slant height

So, The surface area of right regular hexagonal pyramid = \frac{3\sqrt{3}}{2}\times 3^{2} + 3 \times 3 \sqrt{6^{2}+ 3\times \frac{3^{2}}{4}}

Or, The surface area of right regular hexagonal pyramid = \frac{3\sqrt{3}}{2}\times 9 + 9 \sqrt{36+ 3\times \frac{9}{4}}

Or,  The surface area of right regular hexagonal pyramid = 23.38 + 9 × \frac{171}{4}

∴  The surface area of right regular hexagonal pyramid = 23.38 + 9 × 6.538

I.e The surface area of right regular hexagonal pyramid = 23.38 + 58.842

So,  The surface area of right regular hexagonal pyramid = 82.222 cm³ Answer

6 0
4 years ago
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