20 quarters and 2 dimes!! (Take a look at my question if possible!?)
We have been given that a line
passes through the point (10, 3) and is parallel to the line
. We are asked to find the y-intercept of the line.
First of all we will rewrite our given equation in slope-intercept form as:




We know that slope of parallel lines is equal, so slope of parallel line to our given line would be
.
Now we will use slope-intercept form of equation to find y-intercept.
, where,
m = Slope,
b = The y-intercept.
Let us substitute
and coordinates of point
in above equation as:





Therefore, the y-intercept is 7 and our required equation would be
.
Check the picture below
make sure your calculator is in Degree mode.
Answer:
The surface area of right regular hexagonal pyramid = 82.222 cm³
Step-by-step explanation:
Given as , for regular hexagonal pyramid :
The of base side = 3 cm
The slant heights = 6 cm
Now ,
The surface area of right regular hexagonal pyramid = 
Where a is the base side
And h is the slant height
So, The surface area of right regular hexagonal pyramid = 
Or, The surface area of right regular hexagonal pyramid = 
Or, The surface area of right regular hexagonal pyramid = 23.38 + 9 ×
∴ The surface area of right regular hexagonal pyramid = 23.38 + 9 × 6.538
I.e The surface area of right regular hexagonal pyramid = 23.38 + 58.842
So, The surface area of right regular hexagonal pyramid = 82.222 cm³ Answer