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Ira Lisetskai [31]
3 years ago
10

C) The phone case you want to buy is marked down 30%, and you have a 25% off

Mathematics
2 answers:
mestny [16]3 years ago
6 0
Answer:
Yes you can find the original price which is 570
Explanation:
Since it is already marked down 30% you would calculate that
42/.30=140
Then because you have a 25% coupon you would calculate
140/.25=560
Nimfa-mama [501]3 years ago
5 0

Answer: Yes, you can find the original price of the phone case. The phone case was $560

Step-by-step explanation:

42.00 divided by 25% is $168

$168 divided by 30% is $560

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Jay is paid £2000 each month. He saves 6% of the £2000 each month. How many months will it take Jay to save £480? ​
BARSIC [14]

Answer:

4 months

Step-by-step explanation:

(2000 *6)/100 = 120

120x = 480

X = 480/120

X = 4 months

4 0
3 years ago
Please use the figure below to solve for both x and y
kkurt [141]

Answer:

x=10°

y = 12°

Step-by-step explanation:

<TSV = 5x + 4x = 90°

=> 9x = 90°

Divide by 9,

x = 10°

<RSU = 10y + 10° + 5x = 180°

=> 10y + 10° + 5*10° = 180°

=> 10y + 10° + 50° = 180°

=> 10y + 60° = 180°

Subtract 60° on both sides,

10y = 180° - 60° = 120°

Divide by 10,

y = 120° / 10 = 12°

3 0
3 years ago
Sam is a waiter at a local restaurant where he earns wages of $7 per hour. Sam figures that he also earns about $5 in tips for e
mote1985 [20]
<span>C. E(n)=5n+42

5 times the number of people + 7 times 6
</span>
8 0
3 years ago
Read 2 more answers
Factor out the greatest common factor. 10a3b−6a2b2
podryga [215]

Answer:

2a^2b(5a-3b)

If not then the other way is

5a-3b

Step-by-step explanation:

The GCF of 10a^3b and -6a^2b^2 is 2a^2b

So divide by that you will get

2a^2b(5a-3b)

4 0
3 years ago
20 points if you help me solved this problem plz it’s urgent someone plz help me I need help! Will mark you as brainiest!
deff fn [24]

Answer:  see below

<u>Step-by-step explanation:</u>

C(x) = 39 when 0 < x ≤ 1.0

C(x) = 63 when 1.0 < x ≤ 2.0

C(x) = 87 when 2.0 < x ≤ 3.0

C(x) = 111 when 3.0 < x ≤ 4.0

C(x) = 135 when 4.0 < x ≤ 5.0

C(x) = 159 when 5.0 < x ≤ 6.0

Based on the information I provided above, the answers are:

a) x= 0.6, C(x) = 1.0

   x = 1.0, C(x) = 39

   x = 1.1,  C(x) = 63

   x = 2.5, C(x) = 87

   x = 3.0, C(x) = 87

   x = 4.8, C(x) = 135

   x = 5.0, C(x) = 135

   x = 5.3, C(x) = 159

b) If C(x) = 87, then 2.0 < x ≤ 3.0

c) Domain (all possible x-values): 0 < x ≤ 6.0

d) Range (all possible y-values): {39, 63, 87, 111, 135, 159}

3 0
3 years ago
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