Answer:
<h2>Letter B</h2>
Explanation:
because density is an INTENSIVE PROPERTY not an EXTENSIVE.
Answer:
25.6 %.
Explanation:
- To calculate the % of Cl in KClO₄:
<em>% Cl = [Atomic mass of (Cl)/molar mass of KClO₄] x 100</em> = [(35.5 g/mol)/(138.55 g/mol)] x 100 = <em>25.62 % ≅ 25.6 %.</em>
Answer:
90.5mL is the volume of the gas at STP
Explanation:
It is possible to find volume of a gas when conditions of temperature and pressure change using combined gas law:

Where P is pressure, V is volume and T is absolute temperature. 1 is initial conditions and 2 final conditions.
If initial conditions are 1.08atm, 80.0mL and absolute temperature is (-12.5°C + 273.15) = 260.65K.
And STP are 1atm of pressure and 273.15K of absolute temperature. Replacing:

V₂ = <em>90.5mL is the volume of the gas at STP</em>
Explanation:
First thing first, you mistyped the specific heat of water, which should be
c
water
=
4.18
J
g
∘
C
Now, a substance's specific heat tells you how much heat is required to increase the temperature of
1 g
of that substance by
1
∘
C
.
In the case of water, you would need
4.18 J
to increase the temperature of
1 g
of water by
1
∘
C
.
Notice that your sample of water has a mass of
1 g
as well, which means that the only factor that will determine the amount of heat needed will be the difference in temperature.
The equation that establishes a relationshop between heat and change in temperature looks like this
q
=
m
⋅
c
⋅
Δ
T
, where
q
- heat absorbed
c
- the specific heat of the substance, in your case of water
Δ
T
- the change in temperature, defined as the difference between the final temperature and the initial temperature
Plug in your values and solve for
q
to get
q
=
1.00
g
⋅
4.18
J
g
⋅
∘
C
⋅
(
83.7
−
26.5
)
∘
C
q
=
239.096 J
Rounded to three sig figs, the answer will be
q
=
239 J
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