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photoshop1234 [79]
3 years ago
9

The initial temperature of the water is 25 C. After the reaction, the temperature of the water is 62.8 C. Disregarding any heat

loss to the walls of the container, calculate the Hr0. The specific heat of water is 4.18J/(g•k).
Chemistry
1 answer:
Tom [10]3 years ago
4 0

Answer: The answer would be C. Please give me a thanks :) bye!

Explanation:

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An alkane with the formula C6H14 can be prepared by hydrogenation of either of two precursor alkenes having the formula C6H12.
ankoles [38]
Two precursor alkenes

    H₃C  CH₃
         I   I
H₂C=C-CH-CH₃    2,3-dimethyl-1-butene

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alkane

   H₃C     CH₃
        I      I
H₃C-CH-CH-CH₃    2,3-dimethylbutane

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6 0
3 years ago
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What is the boiling point elevation constant, Kb, of diethyl ether if 38.2 g of the nonelectrolyte benzophenone, C6H5COC6H5, dis
kakasveta [241]

Answer: the boiling point elevation constant is 1.73^0C/m

Explanation:

Elevation in boiling point is given by:

\Delta T_b=i\times K_b\times m

\Delta T_b=T_b-T_b^0= = Elevation in boling point

i= vant hoff factor = 1 (for non electrolyte)

K_b =boiling point constant = ?

m= molality

\Delta T_b=i\times K_b\times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}

Weight of solvent (diethylether)= 330 g = 0.33 kg

Molar mass of solute (benzophenone)= 182 g/mol

Mass of solute (benzophenone) = 38.2 g

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K_b=1.73^0C/m

Thus the boiling point elevation constant is 1.73^0C/m

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