The measure of PQS is 38°. What is the measure, in degrees, of PSQ?

IS THIS CORRECT??????????

Alika [10]

The correct answers are the 3rd and 4th ones.

7 0

3 years ago

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The axis of the sphere below is 16 units in length. What is the surface area of the sphere?.

Nataly_w [17]

There are enough information's already given in the question. Based on those information's that answer can be easily deduced.
Radius of the sphere = 8 units
Then
Surface area of the sphere = 4 *pi * r^2
= 4 * pi * (8)^2
= 4 * pi * 64
= 256pi
I hope that this answer has come to your help.

5 0

3 years ago

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What is the radius for the circle given by the equation x^2+(y -3)^2 = 21

MatroZZZ [7]

$\bf\textit{equation of a circle}\\\\(x- h)^2+(y- k)^2= r^2\qquadcenter~~(\stackrel{}{ h},\stackrel{}{ k})\qquad \qquadradius=\stackrel{}{ r}\\\\[-0.35em]\rule{34em}{0.25pt}\\\\x^2+(y-3)^2=21\implies (x-0)^2+(y-3)^2=(\sqrt{21})^2\qquad \begin{cases}center~(0,3)\\r=\sqrt{21}\end{cases}\\\\\\r\approx 4.58257569495584000659\implies r = \stackrel{\textit{rounded up}}{4.583}$

3 0

3 years ago

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A manufacturer of chocolate candies uses machines to package candies as they move along a filling line. Although the packages ar

Elenna [48]

Answer:

We conclude that the mean amount packaged is equal to 8.17 ounces.

Step-by-step explanation:

We are given that in a particular sample of 50 packages, the mean amount dispensed is 8.171 ounces, with a sample standard deviation of 0.052 ounces.

Let $\mu$ = population mean amount packaged.

So, Null Hypothesis, $H_0$ : $\mu$ = 8.17 ounces {means that the mean amount packaged is equal to 8.17 ounces}

Alternate Hypothesis, $H_A$ : $\mu\neq$ 8.17 ounces {means that the mean amount packaged is different from 8.17 ounces}

The test statistics that will be used here is One-sample t-test statistics because we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean amount dispensed = 8.171 ounces

s = sample standard deviation = 0.052 ounces

n = sample of packages = 50

So, the test statistics = $\frac{8.171-8.17}{\frac{0.052}{\sqrt{50} } }$ ~ $t_4_9$

= 0.1359

The value of t-test statistics is 0.1359.

Also, the P-value of test-statistics is given by;

the meaning of the p-value is that the p-value is the probability of obtaining a sample mean that is equal to or more extreme than 0.001 ounces away from8.17 if the null hypothesis is true.

P-value = P( $t_4_9$ > 0.136) = More than 40% {from the t-table}

Since the P-value of our test statistics is more than the level of significance of 0.01, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that the mean amount packaged is equal to 8.17 ounces.

6 0

3 years ago

What adds to make -7 and times to make +10

pav-90 [236]

17
it's 17+(-7)=10
i hope that answers your problem

8 0

3 years ago

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