The fewest number of days over which the tournament can take place is 5 days.
<h3>How to calculate the number of days?</h3>
As each team plays with other team Once and we have total 5 teams so number of matches will be (4+3+2+1)
Counted as team 1 plays with all other teams = 4 matches
Team 2 plays with team 3,4,5 =3 matches
Team 3 play with team 4,5=2 match
And the last match is between team 4 and team5
Total match = 10 and can be played two matches per day:
Number of days = 10/2
= 5 days.
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Answer:
12m^2+14m
Step-by-step explanation:
The "^means exponet" Hope I made your day
:)
Answer:
No solutions
Step-by-step explanation:
i did this via substitution so i hope it isn't a problem
3x+y=4
6x+2y=−4
Step: Solve 3x+y=4for y:
3x+y+−3x=4+−3x(Add -3x to both sides)
y=−3x+4
Step: Substitute−3x+4foryin6x+2y=−4:
6x+2y=−4
6x+2(−3x+4)=−4
8=−4(Simplify both sides of the equation)
8+−8=−4+−8(Add -8 to both sides)
0=−12
so there are no solutions
hope this helps!!
The equation represents a line that passes through(4, 1/3) and has a slope of 3/4 option A; y - 1/3 = 3/4 ( x - 4).
<h3>What is the Point-slope form?</h3>
The equation of the straight line has its slope and given point.
If we have a non-vertical line that passes through any point(x1, y1) has gradient m. then general point (x, y) must satisfy the equation
y-y₁ = m(x-x₁)
Which is the required equation of a line in a point-slope form.
we know that
The equation of the line into point-slope form is equal to
y-y₁ = m(x-x₁)
we have
(x₁, y₁) = (4, 1/3)
m = 3/4
substitute the given values
y-y₁ = m(x-x₁)
y - 1/3 = 3/4 ( x - 4)
therefore,
y minus StartFraction one-third EndFraction equals StartFraction 3 Over 4 EndFraction left-parenthesis x minus 4 right-parenthesis.(x – 4)
Thus, option A is correct.
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Answer:
see explanation
Step-by-step explanation:
look at the photo
