1) The ball's position is described by:
s(t) = 4.9t² + 450
We want to find the velocity, which is the 1st-order derivative of the displacement function (I assume this is an introductory calculus class)
s'(t) = v(t) = 9.8t
We get this by multiplying 4.9 x 2 and reducing the exponent by 1. Now we simply plug 5 in for t.
v(5) = 9.8* 5
v(5) = 49m/s
2) Our cost function is C(x) = x² - 10,000
To find the average rate of change between these units, we use this formula:
( C(101) - C(100) ) ÷1 .
We find the change in C, and divide by the change in x, which is just one.
C(101) = 101² - 10,000
C(101) = 201
C(100) = 100² - 10,000
C(100= 0
C(101) - C(100) = 201
Average rate of change in cost is 201 dollars/ unit between the two points.
This is easy 4x+12 the answer
Answer: 0.10
Step-by-step explanation: The type 2 error is committed when the alternative hypothesis is rejected when it should have been accepted causing the researcher to accept the null hypothesis which is false.
Power is the probability of avoiding a type 2 error. That is ;
Power = 1 - P(type 2 error)
Given that power = 0.90 ; P(type 2 error) = probability of committing a type 2 error.
P(type 2 error)' = 1 - P(type 2 error) = Probability of not committing or avoiding a type 2 error
0.90 = 1 - P(type 2 error)
P(type 2 error) = 1 - 0.90
P(type 2 error) = 0.10
The 1st Option Is A Function
