Answer:
10 were successful
Step-by-step explanation:
40x25%=10
Each element of the matrix are multiplied by the scalar to form a matrix of
same size as the original matrix in matrix scalar multiplication.
Reasons:
The matrix <em>A</em> is presented as follows;
![A = {\left[\begin{array}{ccc}4&6&8\\6&8&10\end{array}\right]}](https://tex.z-dn.net/?f=A%20%3D%20%7B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%266%268%5C%5C6%268%2610%5Cend%7Barray%7D%5Cright%5D%7D)
Using the multiplication of a matrix and a scalar, we have;
![60 \cdot A = 60 \cdot \left[\begin{array}{ccc}4&6&8\\6&8&10\end{array}\right] = \left[\begin{array}{ccc}60 \times 4&60 \times 6&60 \times 8\\60 \times 6&60 \times 8&60 \times 10\end{array}\right] = \left[\begin{array}{ccc}\mathbf{240}&\mathbf{360}&\mathbf{480}\\\mathbf{360}&\mathbf{480}&\mathbf{600}\end{array}\right]](https://tex.z-dn.net/?f=60%20%5Ccdot%20A%20%3D%2060%20%5Ccdot%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%266%268%5C%5C6%268%2610%5Cend%7Barray%7D%5Cright%5D%20%3D%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D60%20%5Ctimes%204%2660%20%5Ctimes%206%2660%20%5Ctimes%208%5C%5C60%20%5Ctimes%206%2660%20%5Ctimes%208%2660%20%5Ctimes%2010%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cmathbf%7B240%7D%26%5Cmathbf%7B360%7D%26%5Cmathbf%7B480%7D%5C%5C%5Cmathbf%7B360%7D%26%5Cmathbf%7B480%7D%26%5Cmathbf%7B600%7D%5Cend%7Barray%7D%5Cright%5D)
Therefore;
![60 \cdot A = \left[\begin{array}{ccc}240\4&360&480\\360&480&600\end{array}\right]](https://tex.z-dn.net/?f=60%20%5Ccdot%20A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D240%5C4%26360%26480%5C%5C360%26480%26600%5Cend%7Barray%7D%5Cright%5D)
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C)
Area of full triangle
1/2(8)(6)=24cm^2
Area of non shaded triangle
1/2(4)(3)=6cm^2
Area of full minus area of small triangle
24-6=18cm^2
D)
Area of Big rectangle
(4)(12)=48
Area of non shaded triangle
1/2(9)(4)=18
Area of Big rectangle minus non shaded triangle
48-18=30cm^2
The (i,j) minor of a matrix A is the matrix Aij obtained by deleting row i and column j from A it is true.
The (i,j) minor of a matrix A is the matrix Aij obtained by deleting row i and column j from A. A determinant of an n×n matrix can be defined as a sum of multiples of determinants of (n−1)×(n−1) sub matrices.
This is done by deleting the row and column which the elements belong and then finding the determinant by considering the remaining elements. Then find the co factor of the elements. It is done by multiplying the minor of the element with -1i+j. If Mij is the minor, then co factor,
+
.
Each element in a square matrix has its own minor. The minor is the value of the determinant of the matrix that results from crossing out the row and column of the element .
Learn more about the minor of the matrix here:
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