D NACL because it is ionic bond and all the others are covalent
Sand and water can be separated by any of the following methods:
1. Sedimentation and decantation: This method involves the mixture being kept undisturbed for some time. After some time, sand being heavier and insoluble in water, settles down at the bottom of container. Now, water is poured into another container to separate it from sand.
2. Filtration: This method involves the mixture being passed through a filter paper (a filter with very fine pores). Sand particles being larger in size are retained by the filter paper and get separated from water.
I hope this helps! :D
Answer:
E) All three samples have the same number of hydrogen atoms
Explanation:
The statements are:
A) Sample A has more hydrogen atoms than sample B or sample C.
B) Sample B has more hydrogen atoms than sample A or sample C.
C) Sample C has more hydrogen atoms than sample A or sample B
D) Both samples A and C have the same number of hydrogen atoms, but more than in sample B.
E) All three samples have the same number of hydrogen atoms
Hydrogens in sample A are:
180g × (1mol Glucose / 180.156g) × (12mol H / 1 mol Glucose) =<em> 12 moles of H</em>
Hydrogens in sample B are:
90g Glucose × (1mol Glucose / 180.156g) × (12mol H / 1 mol Glucose) =<em> 6 moles of H</em>
90g mannose× (1mol Mannose / 180.156g) × (12mol H / 1 mol Glucose) =<em> 6 moles of H</em>
<em>Total moles: 12</em>
Hydrogens in sample C are:
180g × (1mol Mannose / 180.156g) × (12mol H / 1 mol Glucose) =<em> 12 moles of H</em>
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Thus, right answer is:
<em>E) All three samples have the same number of hydrogen atoms</em>
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I hope it helps!
