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3 years ago

What is the [OH-] in a solution with a pol of 7.86?

Chemistry

1 answer:

yulyashka [42]3 years ago

3 0

Answer:

pH of 7.86, then the [OH-] is equal to 10^(14-7.86) = 10^6.14 M

Explanation:

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n a coffee cup calorimeter, 100.0 mL of 1.0M NaOH and 100.0 mL of 1.0M HCl are mixed. Both solutions were originally at 24.6 deg

RoseWind [281]

Answer:

Explanation:

mass of the solution = volume x density = 200 x 1 = 200 gm

heat absorbed = m x s x Δ t , s is specific heat , Δt is rise in temperature

= 200 x 4.18 x ( 31.3 - 24.6 )

= 5601 J .

This is the enthalpy change required.

3 0

4 years ago

A weather balloon was initially at a pressure of 0.950 atm, and its volume was 35.0 L. The pressure decreased to 0.750 atm, with

puteri [66]

Answer: The change in volume will be 9.30 L

Explanation:

To calculate the new pressure, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.

The equation given by this law is:

$P_1V_1=P_2V_2$

where,

$P_1\text{ and }V_1$ are initial pressure and volume.

$P_2\text{ and }V_2$ are final pressure and volume.

We are given:

$P_1=0.950atm\\V_1=35.0L\\P_2=0.750atm\\V_2=?L$

Putting values in above equation, we get:

$0.950\times 35.0L=0.750\times V_2\\\\V_2=44.3L$

The change in volume will be (44.3-35.0)L = 9.30 L

7 0

3 years ago

Need answer to this question asap. it is worth 10 points

andrey2020 [161]

The molecular formula of the liquid : C₆H₁₂

<h3>Further explanation</h3>

Given

molar ratio C H = 1.2 : 0.12

0.12 g at STP gave 32 cm³(0.032 L)

Required

The molecular formula

Solution

At STP, 1 mol = 22.4 L, so for 0.032 L :

mol = 0.032 : 22.4

mol = 0.00143

Molar mass (M) of liquid :

M = mass : mol

M = 0.12 g : 0.00143 mol

M = 83.92≈84 g/mol

C : H = 1 : 2

(CH₂)n=84

(12+2.1)n=84

(14)n=84

n=6

(CH₂)₆=C₆H₁₂

3 0

3 years ago

How many hydrogen atoms are in 1 molecule of C3H7O

Zarrin [17]

Answer:

Explanation:

it has no tiny number on it

8 0

3 years ago

Read 2 more answers

a 5L container contains 3 moles of helium and 4 moles of hydrogen at a pressure of 9 atms maintaining a constant T and additiona

Stells [14]

Answer:

7.71 atm

Explanation:

Given the following data:

$V = 5 L$

$n_{He} = 3 mol$

$n_{H_2} = 4 mol$

$p_1 = 9 atm$

$T = const$

According to the ideal gas law, we know that the product between pressure and volume of a gas is equal to the product between moles, the ideal gas law constant and the absolute temperature:

$pV = nRT$

Since the temperature and the ideal gas constant are constants, as well as the fixed container volume of 5 L, we may rearrange the equation as:

$\frac{p}{n}=\frac{RT}{V}=const$

This means for two conditions, we'd obtain:

$\frac{p_1}{n_1}=\frac{p_2}{n_2}$

Given:

$p_1 = 9 atm$

$n_1 = n_{initial total} = n_{He} + n_{H_2} = 3 mol + 4 mol = 7 mol$

$n_2 = n_{final total} = n_{He} + n_{H_2} = 3 mol + 4 mol + 2 mol = 9 mol$

Solve for the final pressure:

$p_2 = p_1\cdot \frac{n_2}{n_1}$

Now, according to the Dalton's law of partial pressures, the partial pressure is equal to the total pressure multiplied by the mole fraction of a component:

$p_{H_2}=\chi_{H_2}p_2$