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Gala2k [10]
3 years ago
6

What is the method use to separate sand and water​

Chemistry
1 answer:
Slav-nsk [51]3 years ago
7 0

Sand and water can be separated by any of the following methods:

1. Sedimentation and decantation: This method involves the mixture being kept undisturbed for some time. After some time, sand being heavier and insoluble in water, settles down at the bottom of container. Now, water is poured into another container to separate it from sand.

2. Filtration: This method involves the mixture being passed through a filter paper (a filter with very fine pores). Sand particles being larger in size are retained by the filter paper and get separated from water.

I hope this helps! :D

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Nana76 [90]
Hey :)

Air pollution

Hope this helps!

Good luck in your test :)
7 0
4 years ago
Read 2 more answers
Explain why aluminum does not react with potassium nitrate (KNO3) although it reacts with copper nitrate.
Kipish [7]

Answer:

Potassium nitrate react with aluminum to produce potassium aluminate, aluminum oxide and nitrogen. This reaction takes place at a temperature near 400°C.

Explanation:

6KNO3 + 10Al → 6KAlO2 + 2Al2O3 + 3N2

4 0
3 years ago
Phase change occurs in which of the following
olchik [2.2K]

When something changes state.

For example solid to a liquid

Liquid to a gas

5 0
3 years ago
Read 2 more answers
When 2.714 g of AX (s) dissolves in 127.4 g of water in a coffee-cup calorimeter the temperature rises from 23.3 °C to 37.1 °C.
MakcuM [25]

Answer : The enthalpy change for the solution is 166.34 kJ/mol

Explanation :

First we have to calculate the enthalpy change of the reaction.

Formula used :

\Delta H=mC\Delta T\\\\\Delta H=mC(T_2-T_1)

where,

\Delta H = change in enthalpy = ?

C = heat capacity of water = 4.18J/g.K

m = total mass of sample = 2.174 + 127.4 = 129.6 g

T_1 = initial temperature = 23^oC=273+23=296K

T_2 = final temperature = 37.1^oC=273+37.1=310.1K

Now put all the given values in the above expression, we get:

\Delta H=mC(T_2-T_1)

\Delta H=129.6g\times 4.18J/g.K\times (310.1-296)K=7638.36J

Now we have to calculate the moles of AX added to water.

\text{ Moles of }AX=\frac{\text{ Mass of }AX}{\text{ Molar mass of }AX}=\frac{2.714g}{59.1097g/mole}=0.04592moles

Now we have to calculate the enthalpy change for the solution.

As, 0.04592 moles releases heat = 7638.36 J

So, 1 moles releases heat = \frac{7638.36}{0.04592}=166340.59J=166.34kJ

Therefore, the enthalpy change for the solution is 166.34 kJ/mol

7 0
3 years ago
In this problem, you will use Lenz's law to explore what happens when an electromagnet is activated a short distance from a wire
Vsevolod [243]

Answer:

The correct answer is Option A (There is no magnetic flux through the wire loop.)

Explanation:

Magnetic flux measures the entire magnetic field that passes through the wire loop.

The right hand rule can be demonstrated on how magnetic flux is generated through the moving current in the wire loop. The magnetic flux through the wire loop  will decrease as it moves upward through the magnetic field region.

If the direction of the vector area of the wire loop is to the right, and the switch is closed, it will push the magnetic flux to the right which will now be increased due to an equal increase in the current in the wire loop. But, when the switch is open, this will halt the movement of current through the wire loop thus affecting the generation of magnetic field. This would make the magnetic flux to be zero.

4 0
4 years ago
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