<u>Answer:</u> The partial pressure of sulfur dioxide gas in the flask is 160 mmHg
<u>Explanation:</u>
We are given:
Moles of sulfur dioxide gas = 0.25 moles
Moles of methane gas = 0.50 moles
Moles of oxygen gas = 0.50 moles
To calculate the mole fraction of sulfur dioxide, we use the equation:
The partial pressure of a gas is given by Raoult's law, which is:
where,
= partial pressure of sulfur dioxide gas
= total pressure = 800 mmHg
= mole fraction of sulfur dioxide = 0.2
Putting values in above equation, we get:
Hence, the partial pressure of sulfur dioxide gas in the flask is 160 mmHg
Answer:
64.0 g/mol.
Explanation:
- Thomas Graham found that, at a constant temperature and pressure the rates of effusion of various gases are inversely proportional to the square root of their masses.
<em>∨ ∝ 1/√M.</em>
where, ∨ is the rate of diffusion of the gas.
M is the molar mass of the gas.
<em>∨₁/∨₂ = √(M₂/M₁)</em>
∨₁ is the rate of effusion of the unknown gas.
∨₂ is the rate of effusion of He gas.
M₁ is the molar mass of the unknown gas.
M₂ is the molar mass of He gas (M₂ = 4.0 g/mol).
<em>∨₁/∨₂ = 0.25.</em>
∵ ∨₁/∨₂ = √(M₂/M₁)
∴ (0.25) =√(4.0 g/mol)/(M₁)
<u><em>By squaring the both sides:</em></u>
∴ (0.25)² = (4.0 g/mol)/(M₁)
∴ M₁ = (4.0 g/mol)/(0.25)² = 64.0 g/mol.
It can fit two more electrons within its valence shell to follow the octet rule. It will have a -2 charge to gain those two electrons to fill its octet.
A. Protons and Neutrons will get u the atomic mass.
Answer:
6.02×10^23 atoms
Explanation:
Avogadros constant is a number that states the amount of atoms in one mole of a substance which is 6.02×10^23 to 3 significant figures.