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3 years ago

Question:

Chemistry

1 answer:

Alecsey [184]3 years ago

5 0

Answer:

The laboratory demonstration consists of the following;

The compounds present in the combustion reaction = Methane, CH₄ and Oxygen, O₂

The chemical equation for the combustion reaction is given as follows;

CH₄ + 2O₂ → CO₂ + 2H₂O

Therefore;

A. The equation given as CH₄ + O → CO₂ is not correct because;

1) Oxygen gas exist as diatomic molecules, O₂, and given that the experiment involves the mixture of gases, the oxygen gas present which can exist as a separate compound, should be represented as O₂

2) The number of oxygen molecules in the reaction is two rather than one

3) The product also includes two molecules of water (vapor) H₂O

B. The correct equation for the reaction should be given as follows;

CH₄ + 2O₂ → CO₂ + 2H₂O

B i) The constituents of the equation is obtained by the knowledge of the fact that the combustion reaction of an organic substance such as methane in the presence of oxygen yields, carbon dioxide and water (vapor)

The equation showing the relative amounts the reacting compounds is by balancing the basic equation of the combustion of methane in the presence of oxygen

Explanation:

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a steel cylinder is left out in the sun the pressure at 2:00 pm was 1014 kpa at 33.0 c at 7:00 am at a temperature of 21.4c what

e-lub [12.9K]

The easiest way is to use the Law of Gay-Lussac. This law states that there is a direct relation between the temperature in Kelvin of a gas and the pressure.

Then, namig p the pressure and T the temperature in Kelvin and using subscripts for every state:

p/T is constant ==> p_1 / T_1 = p_2/T_2

From which you obtain:

p_2 = [p_1 / T_1] * T_2

T_1 = 33.0 + 273.15 = 306.15 K
T _2 = 21.4 + 273.15 = 294.55 K

p_1 = 1014 kPa

p_2 = 1014 kPa * 294.55 K / 306.15 K = 975.6 kPa

5 0

3 years ago

What is the component concentration ratio, [no2−]/[hno2], of a buffer that has a ph of 3.90? (ka of hno2 = 7.1 × 10−4)?

sasho [114]

According to Henderson–Hasselbalch Equation,

pH = pKa + log [Nitrate] / [Nitric Acid]

As, Ka of Nitric Acid = 7.1 × 10⁻⁴
So,
pKa = -log [ 7.1 × 10⁻⁴ ]

pKa = 3.148

So, pH = 3.148 + log [Nitrate] / [Nitric Acid]

3.90 = 3.148 + log [Nitrate] / [Nitric Acid]

3.90 - 3.148 = log [Nitrate] / [Nitric Acid]

0.752 = log [Nitrate] / [Nitric Acid]

Taking Antilog on both sides,

[Nitrate] / [Nitric Acid] = 5.64

8 0

3 years ago

Calculate the displacement (the total volume of the cylinder through which the piston move) of a 5.70L automobile engine in cubi

Novay_Z [31]

Answer:

348 inches³

Explanation:

From our previous knowledge of units conversion:

We know that 1000 cm³ makes 1 Liter.

Thus, for a 5.70 L automobile engine in cubic meters will be:

= 5.70 × 1000 cm³

= 5700 cm³

Now, the displacement of the automobile in cubic inches provided that 1 inch = 2.534 cm is:

⇒ 5700× (1/ (2.54)³) in³

= 5700×0.0610 in³

= 347.7 in³

≅ 348 inches³

4 0

3 years ago

1. Which of the following does NOT indicate that a chemical change may have taken place?

mojhsa [17]

A fracture Formation .
A matter is neither destroyed or created

8 0

3 years ago

I know that the answer is C. 8, but can you explain step by step how to get that answer?

Leya [2.2K]

Answer:

Explanation:

Oxidation:

$Fe^{2+} -->Fe^{3+}+e^{-}$

Reduction:

$Cr_{2}O_{7}^{2-}+6e^{-} -->2Cr^{3+}$

We have to equalise the number of moles of electrons gained and lost in a redox reaction in order to get a balanced reaction.

Hence we have to multiply the oxidation reaction throughout by 6.

and adding the two half-reactions we obtain:

$6Fe^{2+}+Cr_{2}O_{7}^{2-} -->6Fe^{3+}+2Cr^{3+}$

Still the total charge and number of oxygen is not balanced.

Since the reaction takes place in acidic conditions, we will add required number of H+ to the appropriate side to balance the charge and add half the amount of H2O to balance the hydrogen atoms.

We add 14 H+ on LHS and 7H2O on RHS to obtain:

$6Fe^{2+}+Cr_{2}O_{7}^{2-}+14H^{+} -->6Fe^{3+}+2Cr^{3+}+7H_{2}O$

Sum of coefficients of product cations = 6+2 = 8

4 0

3 years ago