The elastic potential energy of a spring can be said to be the energy possessed by a spring due to a force that compresses or stretches the spring. This can also be said to be the work which is done by the applied force against the restoring force of the spring, which is stored as the elastic potential energy.
The elastic potential of a spring can be expressed as:
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We can approach this in another way.
We know that sin(∅) = height / hypotenuse.
Thus, for x, height is 1 and hypotenuse is 3. Using Pythagoras theorem,
3² = 1² + b²
b = √8
cos(x) = b/hypotenuse
cos(x) = √8 / 3
Now, lets consider y:
sec(y) = 1 / cos(y) = 1 / base / hypotenuse = hypotenuse / base
The hypotenuse is 25 and the base is 24. We again apply Pythagoras theorem to find the third side, which works out to be:
height = 7
sin(y) = height / hypotenuse
sin(y) = 7/25
Now, sin(x + y) =
sin(x)cos(y) + sin(y)cos(x)
= (1/3)(24/25) + (√8 / 3)(7/25)
= 8/25 + 7√8/75
= (24 + 14√2) / 75
Answer:
Explanation:
It is given that,
The planet Mercury travels in an elliptical orbit with eccentricity 0.206, e = 0.206
The minimum distance from the sun,
The relation between the minimum and the maximum distance from the sun is given by :
a is the maximum distance from the sun
or
So, the maximum distance from the sun is . Hence, this is the required solution.
Answer:
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Explanation:
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