Answer:
a = 5
Step-by-step explanation:
According to the factor theorem, if x + 2 is a factor, then by dividing the polynomial by the binomial, we are meant not to have a remainder
In this case, the remainder would be zero
So, if we set the binomial equals zero and substitute the x-value into the polynomial, we are supposed to have 0
So we have this as;
x + 2 = 0
x = -2
-2^3 -2(-2)^2 -2(a) + 6 = 0
-8-8-2a + 6 = 0
-16 + 2a + 6 = 0
2a -10 = 0
2a = 10
a = 10/2
a = 5
Basically the Remainder theorem states that the remainder of dividing a polynomial P(x) by (x - a) is given by P(a).
So for example if we divide x^ 2 - 2x + 7 by x - 2 the remainder will be
2^2 - 2(2) + 7 = 7..
If the remainder is 0 then the divisor will be a factor of the polynomial. This is the Factor Theorem and can be used to test if a given polynomial has a factor x-a.
Answer:
d. y =5(1.06)^x
Step-by-step explanation:
growth formula is
y = (1+r)^t
1+r has to be greater than 1
mustangps
Hello from MrBillDoesMath!
Answer:
x = 0, 7
Discussion:
f(g(x)) =
f ( x^2-7x) =
1/ ( x^2 - 7x)
The points NOT in the domain are those where the denominator, x^2 - 7x = 0.
x^2 - 7x = 0 => factor x from each term
x(x-7) = 0 => one or both terms must each 0
x = 0 or x =7
Thank you,
MrB
Answer:
can I see the graphs
Step-by-step explanation:
I cannot see the graph
