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MaRussiya [10]
3 years ago
7

In the diagram below, the letters A, B and C represent three identical satellites and their relative distances from Earth.

Chemistry
2 answers:
Lilit [14]3 years ago
8 0

Answer:

C bc its the furthest from earth

Explanation:

bagirrra123 [75]3 years ago
8 0
C. Bc it’s furthest from earth
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The energy of any one-electron species in its nth state (n = principal quantum number) is given by E = –BZ2 /n2 where Z is the c
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Explanation:

(a) The given data is as follows.

            B = 2.180 \times 10^{-18} J

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Now, for the first excited state n_{f} = 2; and n_{i} = \infinity if it is ionized.

Therefore, ionization energy will be calculated as follows.

         I.E = \frac{-Bz^{2}}{\infinity^{2}} - (\frac{-2.180 \times 10^{-18} J /times (4)^{2}}{(2)^{2}})

              = 8.72 \times 10^{-18} J

Converting this energy into kJ/mol as follows.

           8.72 \times 10^{-18} J \times 6.02 \times 10^{23} mol  

           = 5249 kJ/mol

Therefore, the ionization energy of the Be^{3+} ion in its first excited state in kilojoules per mole is 5249 kJ/mol.

(b) Change in ionization energy is as follows.

         \Delta E = -Bz^{2}(\frac{1}{(4)^{2}} - {1}{(2)^{2}}) = \frac{hc}{\lambda}

   \frac{hc}{\lambda} = 0.1875 \times 2.180 \times 10^{-18} J \times (4)^{2}                

        \lambda = \frac{6.626 \times 10^{-34} \times 2.998 \times 10^{8} m/s}{0.1875 \times 2.180 \times 10^{-18} J \times 16}

                     = 303.7 \times 10^{-10} m

or,                 = 303.7^{o}A

Therefore, wavelength of light given off from the Be^{3+} ion by electrons dropping from the fourth (n = 4) to the second (n = 2) energy levels 303.7^{o}A.

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Substances that exist in solution almost completely as ions are called strong electrolytes. Therefore, the answer is C.

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