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Ray Of Light [21]
3 years ago
10

Please help if you can help me, you can have all my points and be brainlest!

Chemistry
1 answer:
brilliants [131]3 years ago
5 0

Answer:

Erosion by water

Explanation:

Moving water carrying away small pieces of rock is erosion by water.

E.g when the sea hits on the cliff and then takes away the fragments with it

Hope I helped

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When a soda can is dropped, it should not be immediately opened. Why?
Kipish [7]
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7 0
3 years ago
identify the law that explains the following observation nitrogen dioxide can be formed by reacting 14 G of nitrogen with 32 gra
Mrrafil [7]

Answer:

The law of definite proportions. I had the same question for chemistry and this is what they said was right so I got 100%.

Explanation:

8 0
3 years ago
use the equation 2C4H10 +13O2--&gt;8CO2+10H2O to find how many moles of oxygen would react with .425 mol C4H10
antoniya [11.8K]
2C4H10 + 13O2  →  8CO2 + 10H2O Since the equation is balanced, we can set up a proportion: 13 moles of O2 react with 2 moles of C4H10x  moles of O2 react with 0.425 moles of C4H10 13 → 2x → 0.425 x = 13 * 0.425 / 2 = 2.7625 <span>2.7625 moles of O2 react with 0.425 moles of C4H10</span> 
6 0
2 years ago
Read 2 more answers
. In a titration, a 25.0 mL sample of 0.150 M HCl is neutralized with 44.45 mL of Ba(OH)2. a. Write the balanced molecular equat
choli [55]

Answer:

Equation of reaction:

a) 2HCl + Ba(OH)2 ==> CaCl2 + 2H2O

b) Molarity of base = 0.042 M.

Explanation:

Using titration equation

CAVA/CBVB = NA/NB

Where NA is the number of mole of acid = 2

NB is the number of mole of base = 1

CA is the molarity of acid =0.15M

CB is the molarity of base = to be calculated

VA is the volume of acid = 25 ml

VB is the volume of base = 44.45mL

Substituting

0.15×25/CB×44.45 = 2/1

Therefore CB =0.15×25×1/44.45×2

CB = 0.042 M.

5 0
2 years ago
Mrs. Sikora purchases chlorpheniramine over-the-counter for her allergies. Which side effect would Mrs. Sikora likely experience
galina1969 [7]

Answer:

drowsiness

Explanation:

4 0
2 years ago
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