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3 years ago

8

ANDWER CHOICES: 14cm 20cm 8cm 6cm I NED HELP ASAP!!!!

1 answer:

meriva3 years ago

7 0

20 cm is the answer to the question

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Please please help me. i’ll literally send you money. i need to pass please help

mihalych1998 [28]

<h3>Answer: Approximately 6.4 units</h3>

==================================================

Explanation:

The origin is the point (0,0)

Use the distance formula to find the distance from (0, 0) to (4, -5)

Let

$(x_1,y_1) = (0,0)\\\\(x_2,y_2) = (4,-5)\\\\$

be our two points. Plug those values into the distance formula below and use a calculator to compute

$d = \sqrt{\left(x_1-x_2\right)^2+\left(y_1-y_2\right)^2}\\\\d = \sqrt{\left(0-4\right)^2+\left(0-(-5)\right)^2}\\\\d = \sqrt{\left(0-4\right)^2+\left(0+5\right)^2}\\\\d = \sqrt{\left(-4\right)^2+\left(5\right)^2}\\\\d = \sqrt{16+25}\\\\d = \sqrt{41} \ \text{ exact distance}\\\\d \approx 6.40312 \ \text{ approximate distance}\\\\d \approx 6.4\\\\$

The distance between the two points (0,0) and (4,-5) is approximately 6.4 units.

6 0

4 years ago

Calculate a_57 for the sequence {a_n}={-6,-9/2,-3,-3/2,0}

Archy [21]

Answer:the 57th term is 78

Step-by-step explanation:

The sequence is an arithmetic sequence. The formula for determining the nth term of an arithmetic sequence is expressed as

Tn = a + (n - 1)d

Where

a represents the first term of the sequence.

d represents the common difference.

n represents the number of terms in the sequence.

From the information given,

a = - 6

d =3/2

n = 57

We want to determine the value if the 57th term, T57. Therefore,

T57 = - 6 + (57 - 1) ×3/2

T57 = - 6 + 56 × 3/2 = - 6 + 84

T57 = 78

3 0

3 years ago

Lee is replacing the carpet in the living room of the house. The living room is a rectangle 20 1/4 feet long 13 1/3 wide. A clos

gtnhenbr [62]

Answer:

100 ft

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Mathematically verify the outlier(s) in the data set using the 1.5 rule.

statuscvo [17]

Given:

The data values are:

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

To find:

The outliers of the given data set.

Solution:

We have,

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

Divide the data set in two equal parts.

(7, 8, 11, 13, 14, 14), (14, 15, 16, 16, 18, 19)

Divide each parenthesis in two equal parts.

(7, 8, 11), (13, 14, 14), (14, 15, 16), (16, 18, 19)

Now,

$Q_1=\dfrac{11+13}{2}$

$Q_1=\dfrac{24}{2}$

$Q_1=12$

And

$Q_3=\dfrac{16+16}{2}$

$Q_3=\dfrac{32}{2}$

$Q_3=16$

The interquartile range is:

$IQR=Q_3-Q_1$

$IQR=16-12$

$IQR=4$

The data values lies outside the interval $[Q_1-1.5IQR,Q_3+1.5IQR]$ are known as outliers.

$[Q_1-1.5IQR,Q_3+1.5IQR]=[12-1.5(4),16+1.5(4)]$

$[Q_1-1.5IQR,Q_3+1.5IQR]=[12-6,16+6]$

$[Q_1-1.5IQR,Q_3+1.5IQR]=[6,22]$

All the data values lie in the interval [6,22]. So, there are no outliers.

Hence, the correct option is 4.

3 0

3 years ago

I need help with question 1 please. I’ll mark brainliest

Dvinal [7]

It is x^2-2x-9 since u just subtract both equations

4 0

3 years ago

Read 2 more answers