Based on the trend of the increase in children born out of wedlock, if this trend keeps increasing, the year with 67% of babies born out of wedlock will be 2055 .
<h3>What year will 67% of babies be born to unmarried parents?</h3><h3 />
In 1990, the 28% of children were born out of wedlock and this trend was increasing by 0.6% per year.
If the trend continues, the number of years till 67% of children born out of wedlock will be:
= (67% - 28%) / 0.6%
= 65 years
The year will be:
= 1990 + 65
= 2055
The first part of the question is:
According to the National Center for Health Statistics, in 1990, 28% of babies in the United States were born to parents who were not married. Throughout the 1990s, this percentage increased by approximately 0.6 per year.
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Subtract 32 to both sides to the equation becomes -5x^2 + 7x + 9 = 0.
To solve this equation, we can use the quadratic formula. The quadratic formula solves equations of the form ax^2 + bx + c = 0
x = [ -b ± √(b^2 - 4ac) ] / (2a)
x = [ -7 ± √(7^2 - 4(-5)(9)) ] / ( 2(-5) )
x = [ -7 ± √(49 - (-180) ) ] / ( -10 )
x = [ -7 ± √(229) ] / ( -10)
x = [ -7 ± sqrt(229) ] / ( -10 )
x = 7/10 ± -sqrt(229)/10
The answers are 7/10 + sqrt(229)/10 and 7/10 - sqrt(229)/10.
Answer:
Step-by-step explanation:
hello :
here is an solution
Answer:
See answer below:
Step-by-step explanation:
Blue: y=2x+1
Red: y=3x-2
Answer:
(x + 6)(x + 8)
Step-by-step explanation:
Consider the factors of the constant term (48 ) which sum to give the coefficient of the x- term (14 )
The factors are + 6 and + 8
since 6 × 8 = 48 and 6 + 8 = 14
x² + 14x + 48 = (x + 6)(x + 8) ← in factored form