Answer:
So the number of total combinations is 35.
Step-by-step explanation:
We know that Ellen must take 4 courses this semester. She has a list of 3 math courses and 4 science courses.
Therefore, she have total 7 courses.
So, we calculate the number of combinations to choose 4 out of 7 courses.
We get:
So the number of total combinations is 35.
Answer:
32
Step-by-step explanation:
6x+1 / 2x +6 - 5/2
Factor 2 out of the denominator of the first fraction:
6x+1 / 2(x+3) - 5/2
Rewrite 5/2 to have a common denominator with the first fraction:
6x+1/2(x+3) - 5(x+3) / 2(x+3)
Simplify terms:
6x +1 - 5(x+3) / 2(x+3)
Use distributive property:
6x +1 - 5x -15 / 2(x+3)
Combine like terms for final answer:
(x-14) / 2(x+3)
Answer:
1) It is geometric
a) In each trial you can obtain 11 or obtain something else (and fail)
b) Throw 2 dices and watch if the result is 11 or not
c) The probability of success is 1/18
2) It is not geometric, but binomal.
Step-by-step explanation:
1) This is effectively geometric. When you see the sum of 2 dices, you can separate the result in two different outcomes: when the sum is 11 and when the sum is different from 11.
A trial is constituted bu throwing 2 dices and watching if the sum of the dices is 11 or not.
In order to get 11 you need one 5 in one dice and 1 six in another. As a consecuence, you have 2 favourable outcomes (a 5 in the first dice and a 6 in the second one or the other way around). The total amount of outcomes is 6² = 36, and all of them have equal probability. This means that the probability of success is 2/36 = 1/18.
2) This is not geometric distribution. The geometric distribution meassures how many tries do you need for one success. The amount of success in 10 trias follows a binomial distribution.
I think it is 5/12 I hope it’s ok right
