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jekas [21]
3 years ago
15

If the coordinate ( -12, 15 ) was translated according to (x+3, y-2), what would the new coordinate be?

Mathematics
1 answer:
Keith_Richards [23]3 years ago
4 0
(-9,13) hope this helps
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Ellen must take 4 courses this semester. She has a list of 3 math courses and 4 science courses to from which to choose. (a) Ini
prisoha [69]

Answer:

So the number of total combinations is 35.

Step-by-step explanation:

We know that Ellen must take 4 courses this semester. She has a list of 3 math courses and 4 science courses.  

Therefore, she have total 7 courses.  

So, we calculate the number of combinations to choose 4 out of 7  courses.

We get:

C_4^7=\frac{7!}{4!(7-4)!}=35\\

So the number of total combinations is 35.

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4 years ago
What is 4x8 please answer I’ll give you 95 points
Rina8888 [55]

Answer:

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Step-by-step explanation:

8 0
3 years ago
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Algebra problem, please show work!
Brrunno [24]

6x+1 / 2x +6 - 5/2

Factor 2 out of the denominator of the first fraction:

6x+1 / 2(x+3) - 5/2

Rewrite 5/2 to have a common denominator with the first fraction:

6x+1/2(x+3) - 5(x+3) / 2(x+3)

Simplify terms:

6x +1 - 5(x+3) / 2(x+3)

Use distributive property:

6x +1 - 5x -15 / 2(x+3)

Combine like terms for final answer:

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4 0
3 years ago
Hey (; I'm taking this rigorous AP Stat course and I've mastered Binomial Sampling but this Geometric Sampling just has me stump
chubhunter [2.5K]

Answer:

1) It is geometric

a) In each trial you can obtain 11 or obtain something else (and fail)

b) Throw 2 dices and watch if the result is 11 or not

c) The probability of success is 1/18

2) It is not geometric, but binomal.

Step-by-step explanation:

1) This is effectively geometric. When you see the sum of 2 dices, you can separate the result in two different outcomes: when the sum is 11 and when the sum is different from 11.

A trial is constituted bu throwing 2 dices and watching if the sum of the dices is 11 or not.

In order to get 11 you need one 5 in one dice and 1 six in another. As a consecuence, you have 2 favourable outcomes (a 5 in the first dice and a 6 in the second one or the other way around). The total amount of outcomes is 6² = 36, and all of them have equal probability. This means that the probability of success is 2/36 = 1/18.

2) This is not geometric distribution. The geometric distribution meassures how many tries do you need for one success. The amount of success in 10 trias follows a binomial distribution.

4 0
3 years ago
What is 7/12- blank =1/6
arsen [322]
I think it is 5/12 I hope it’s ok right
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3 years ago
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