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Harrizon [31]
3 years ago
10

75 DIVIDE BY 600 EQUALS

Mathematics
1 answer:
ad-work [718]3 years ago
4 0

Answer:

here?

Step-by-step explanation:

75÷600=0.125

if you meant

600÷75=8

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Graph x > -3x>−3x, is greater than, minus, 3.
antiseptic1488 [7]
It just is :). Ok ok
4 0
3 years ago
A person bought some cosmetics from wholesale market at the rate of Rs 360 per dozen he sells it at Rs 80 a pair find the gain p
marusya05 [52]

Answer:

33.33%

Step-by-step explanation:

We need to calculate the <u>unit selling price and cost of each cosmetics.</u>

If a person bought some cosmetics from wholesale market at the rate of Rs 360 per dozen., then for 1 cosmetics, we will say;

x = 1 cosmetic

since 360 = 12 cosmetic

cross multiply

12x = 360

x = 360/12

x = 30

Hence the unit cost price of the cosmetics will be Rs. 30

Similarly, if he sells it at Rs 80 a pair, then he sold one cosmetic at 80/2 = Rs. 40 (a pair is 2 cosmetics)

Selling price per unit = Rs. 40

Cost price per unit = Rs. 30

percent gain = SP-CP/CP * 100%

percent gain = 40-30/30 * 100

percent gain = 10/30 * 100

percent gain = 100/3

percent gain = 33.33%

Hence the percentage gain is 33.33%

5 0
3 years ago
The standard form of an absolute value function is f(x)-a|x-h|+k. Which of the following represents the vertex?
Len [333]

Answer:

(h, k )

Step-by-step explanation:

given the standard form of an absolute function

f(x) = a| x - h | + k , then

vertex = (h, k )

6 0
2 years ago
At which value will the graph of y=tanx have a zero? Please explain the correct answer!
Rina8888 [55]

Answer: None of the above are correct.


Step-by-step explanation:

Given function: y=\tan x

We know that the value of tan x =0 at x=0.

Also, At\ x=\frac{\pi}{3},\ \tan\frac{\pi}{3}=\sqrt{3}

At\ x=\frac{\pi}{2},\ \tan\frac{\pi}{2}=\infty

At\ x=\frac{\pi}{3},\ \tan\frac{\pi}{4}=1

Hence, the only option is correct is "None of the above are correct".

4 0
3 years ago
Find the value of the variable.
Nikolay [14]

we are given that

both sides are equal

so, their length must be equal

HK=\sqrt{(p-1)^2+(5-2)^2}

HK=\sqrt{(p-1)^2+9}

now, we can find other side

JK=\sqrt{(p-7)^2+(5-2)^2}

JK=\sqrt{(p-7)^2+9}

now, we can set them equal

HK=JK

\sqrt{(p-1)^2+9}=\sqrt{(p-7)^2+9}

now, we can take square both sides

(p-1)^2+9=(p-7)^2+9

now, we can solve for p

(p-1)^2=(p-7)^2

p^2-2p+1=p^2-14p+49

-2p+1=-14p+49

12p=48

p=4..............Answer

4 0
3 years ago
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