In 2.5 S, a Car increases its speed from 20.0m/s to 25.0 m/s what is the acceleration of the car

A sinusoidal wave has the following wave function: y(x,t) = (2.5 m) sin[(3.0 m-1) x – (24 s-1) t + π/2] What is the frequency of

Vera_Pavlovna [14]

Answer:

3.82 Hertz

Explanation:

$y = 2.5 Sin\left (3x-24t+\frac{\pi }{2} \right )$

This is the equation of a wave which varies sinusoidally.

The standard equation of a wave is given by

$y = A Sin\left ( kx-\omega t+\phi \right )$

where, A be the amplitude of the wave, k be the wave number, x be the displacement of wave, ω be the angular frequency and t be the time taken, and Ф be the phase angle.

now compare the given equation by the standard equation, we get

k = 3

ω = 24

Ф = π / 2

So, the angular frequency = 24

The relation between the angular frequency and the frequency is given by

ω = 2 x π x f

24 = 2 x 3.14 x f

f = 3.82 Hertz

4 0

3 years ago

Which of the following plays a major role in creating surface currents?

kap26 [50]

I'm pretty sure it is A but I would still check with someone :)

6 0

2 years ago

Read 2 more answers

A 6,000 kg train car is moving to the right at 10 m/s and connects to a 4,000-kg train car that wasn't moving. What is the veloc

vredina [299]

1) The final velocity of the two trains is 6 m/s to the right

2) It is an inelastic collision

Explanation:

1)

We can solve this problem by using the law of conservation of momentum: in fact, in absence of external forces, the total momentum of the two trains must be conserved before and after the collision.

Therefore we can write:

$p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v$

where:

$m_1 = 6,000 kg$ is the mass of the first train

$u_1 = 10 m/s$ is the initial velocity of the first train

$m_2 = 4,000 kg$ is the mass of the second train

$u_2 = 0$ is the initial velocity of the second train (initially at rest)

$v$ is the final combined velocity of the two trains

Solving the equation for v, we find the final velocity of the two trains:

$v=\frac{m_1 u_1 + m_2 u_2}{m_1+m_2}=\frac{(6000)(10)+0}{6000+4000}=6 m/s$

2)

There are two types of collisions:

Elastic collision: in an elastic collision, both the total momentum and the total kinetic energy of the system are conserved
Inelastic collision: in an inelastic collision, only the total momentum is conserved, while the total kinetic energy is not (part of it is converted into thermal energy due to internal frictions)

To verify what type of collision is this, we can compare the total kinetic energy before and after the collision:

Before:

$K=\frac{1}{2}m_1 u_1^2 = \frac{1}{2}(6000)(10)^2=300,000 J$

After:

$K=\frac{1}{2}(m_1 +m_2)v^2 = \frac{1}{2}(6000+4000)(6)^2=180,000 J$

As we can see, the kinetic energy is not conserved, so this is an inelastic collision.

Learn more about momentum here:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

#LearnwithBrainly

3 0

2 years ago

A student has a displacement of 304 m north in 180 s. What was the student's average velocity?

DanielleElmas [232]

Answer:

v = 1.69 m/s

Explanation:

Given that,

Displacement of the student is 304 m due North and it takes 180 s.

We need to find the student's average velocity. Using formula of velocity.

Velocity = displacement/time

$v=\dfrac{304\ m}{180\ s}\\\\v=1.69\ m/s$

Hence, the student's average velocity is 1.69 m/s.

6 0

3 years ago

Neo and Morpheus's masses have gained a velocity (not equal to zero) which means their momentum is now _____ .

Arte-miy333 [17]

<span>Neo and Morpheus's masses have gained a velocity (not equal to zero) which means their momentum is now based on gravity and friction alone.</span>

6 0

2 years ago

Read 2 more answers

In 2.5 S, a Car increases its speed from 20.0m/s to 25.0 m/s what is the acceleration of the car​

In 2.5 S, a Car increases its speed from 20.0m/s to 25.0 m/s what is the acceleration of the car