(A) The total initial momentum of the system is
(1.30 kg) (27.0 m/s) + (23.0 kg) (0 m/s) = 35.1 kg•m/s
(B) Momentum is conserved, so that the total momentum of the system after the collision is
35.1 kg•m/s = (1.30 kg + 23.0 kg) <em>v</em>
where <em>v</em> is the speed of the combined blocks. Solving for <em>v</em> gives
<em>v</em> = (35.1 kg•m/s) / (24.3 kg) ≈ 1.44 m/s
(C) The kinetic energy of the system after the collision is
1/2 (1.30 kg + 23.0 kg) (1.44 m/s)² ≈ 25.4 J
and before the collision, it is
1/2 (1.30 kg) (27.0 m/s)² ≈ 474 J
so that the change in kinetic energy is
∆<em>K</em> = 25.4 J - 474 J ≈ -449 J
Answer:
I dont know what to answer so im just gonna say ok
A circuit with an impedance of 5 ohms and a voltage of 100 volts has a current flow of 20 A.
The expression of an electronic component, circuit, or system's resistance to alternating and/or direct electric current is called impedance, indicated by the letter Z. Resistance and reactance are two distinct scalar (one-dimensional) phenomena that combine to form impedance, a vector (two-dimensional) variable.
= 
(for a pure resistor where Z=R,preserving the form of the DC Ohm's law).
I = 20 A
Therefore, A circuit with an impedance of 5 ohms and a voltage of 100 volts has a current flow of 20 A.
Learn more about impedance here;
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Initial velicity Vo.
Sin(23) = 24.7 / Vo
Vo = 24.7/Sin(23)
V0 = 63.2 m/sec
Answer:
The path difference between the two waves should be one-half of a wavelength
Explanation:
When two beams of coherent light travel different paths, arriving at point P. If the maximum destructive interference is to occur at point P , then the condition for it is that the path difference of two beams must be odd multiple of half wavelength. Symbolically
path difference = ( 2n+1 ) λ / 2
So path difference may be λ/2 , 3λ/ 2, 5λ/ 2 etc .
Hence right option is
The path difference between the two waves should be one-half of a wavelength.
