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Delicious77 [7]

4 years ago

11

A bag of sugar weighs 1.50 lb on earth. what would it weigh in newtons on the moon, where the free-fall acceleration is one-sixt

h that on earth?

1 answer:

Fittoniya [83]4 years ago

8 0

0.25 is the answer :)

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A record turntable is rotating at 33 rev/min. A watermelon seed is on the turntable 4.0 cm from the axis of rotation. (a) Calcul

Annette [7]

Answer:

a) a = 0.477 m/s^2

b) u = 0.04862

Explanation:

Given:-

- The rotational speed of the turntable N = 33 rev/min

- The watermelon seed is r = 4.0 cm away from axis of rotation.

Find:-

(a) Calculate the acceleration of the seed, assuming that it does not slip. (b) What is the minimum value of the coefficient of static friction between the seed and the turntable if the seed is not to slip

Solution:-

- First determine the angular speed (w) of the turntable.

w = 2π*N / 60

w = 2π*33 / 60

w = 3.456 rad/s

- The watermelon seed undergoes a centripetal acceleration ( α ) defined by:

α = w^2 * r

α = 3.456^2 * 0.04

α = 0.477 m / s^2

- The minimum friction force (Ff) is proportional to the contact force of the seed.

- The weight (W) of the seed with mass m acts downwards. The contact force (N) can be determined from static condition of seed in vertical direction.

N - W = 0

N = W = m*g

- The friction force of the (Ff) is directed towards the center of axis of rotation, while the centripetal force acts in opposite direction. The frictional force Ff = u*N = u*m*g must be enough to match the centripetal force exerted by the turntable on the seed.

Ff = m*a

u*m*g = m*a

u = a / g

u = 0.477 / 9.81

u = 0.04862

8 0

3 years ago

A proton moves at constant velocity in the direction, through a region in which there is an electric field and a magnetic field.

dimaraw [331]

Answer:

$F_{net}=0$

Explanation:

It is given that, a proton moves at constant velocity, through a region in which there is an electric field and a magnetic field such that,

The electric field is, E = 800 V/m

Magnetic field, B = 0.25 T

We know that the net force in the region of magnetic and electric field is given by Lorentz forces. But here, the proton moves with constant velocity. So, the net force acting on it is 0.

i.e.

$F_{net}=0$

Hence, this is the required solution.

7 0

3 years ago

Which vector below goes from (0,0) to (1,-3)?

vitfil [10]

I think D. It starts at (0.0) and goes to the correct points so it makes sense

8 0

3 years ago

Read 2 more answers

In a bicycle dynamo,does 1. The permanent magnet surrounds a conducting coil 2. The conducting coil rotates when the rear wheel

atroni [7]

Explanation:

3: the electricity is generated in the permanent magnet

7 0

3 years ago

Read 2 more answers

According to Bernoulli's equation, the pressure in a fluid will tend to decrease if its velocity increases. Assuming that a wind

Pie

Answer:

The pressure drop predicted by Bernoulli's equation for a wind speed of 5 m/s

= 16.125 Pa

Explanation:

The Bernoulli's equation is essentially a law of conservation of energy.

It describes the change in pressure in relation to the changes in kinetic (velocity changes) and potential (elevation changes) energies.

For this question, we assume that the elevation changes are negligible; so, the Bernoulli's equation is reduced to a pressure change term and a change in kinetic energy term.

We also assume that the initial velocity of wind is 0 m/s.

This calculation is presented in the attached images to this solution.

Using the initial conditions of 0.645 Pa pressure drop and a wind speed of 1 m/s, we first calculate the density of our fluid; air.

The density is obtained to be 1.29 kg/m³.

Then, the second part of the question requires us to calculate the pressure drop for a wind speed of 5 m/s.

We then use the same formula, plugging in all the parameters, to calculate the pressure drop to be 16.125 Pa.

Hope this Helps!!!

7 0

3 years ago