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sergejj [24]
3 years ago
9

The potential (relative to infinity) at the midpoint of a square is 3.0 V when a point charge of +Q is located at one of the cor

ners of the square. What is the potential (relative to infinity) at the center when each of the other corners also contains a point charge of +Q?
a) 0 V
b) 3.0 V
c) 9.0 V
d) 12 V
Physics
1 answer:
Sveta_85 [38]3 years ago
4 0

Answer:

d) 12 V

Explanation:

Due to the symmetry of the problem, the potential (relative to infinity) at the midpoint of the square, is the same for all charges, provided they be of the same magnitude and sign, and be located at one of the corners of the square.

We can apply the superposition principle (as the potential is linear with the charge) and calculating the total potential due to the 4 charges, just adding the potential due to any of  them:

V = V(Q₁) + V(Q₂) +V(Q₃) + V(Q₄) = 4* 3.0 V = 12. 0 V

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Rus_ich [418]

Answer:

6.99535\times 10^{-6}\ V/m

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P = Power Output = 1000 W

r = Radius = 35000000 m

\epsilon_0 = Permittivity of free space = 8.85\times 10^{-12}\ F/m

c = Speed of light = 3\times 10^8\ m/s

Intensity of Electric radiation

I=\frac{P}{A}\\\Rightarrow I=\frac{P}{4\pi r^2}\\\Rightarrow I=\frac{1000}{4\pi\times 35000000^2}\ W/m^2

Intensity of Electric radiation

I=\frac{1}{2}c\epsilon_0E_0\\\Rightarrow E_0=\sqrt{\frac{2I}{c\epsilon_0}}\\\Rightarrow E_0=\sqrt{\frac{2\times \frac{1000}{4\pi\times 35000000^2}}{3\times 10^8\times 8.85\times 10^{-12}}}\\\Rightarrow E_0=6.99535\times 10^{-6}\ V/m

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4 years ago
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Answer:

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Several Physics Labs have built experiments called "Kelvins Thunderstorm"

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