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sergejj [24]
2 years ago
9

The potential (relative to infinity) at the midpoint of a square is 3.0 V when a point charge of +Q is located at one of the cor

ners of the square. What is the potential (relative to infinity) at the center when each of the other corners also contains a point charge of +Q?
a) 0 V
b) 3.0 V
c) 9.0 V
d) 12 V
Physics
1 answer:
Sveta_85 [38]2 years ago
4 0

Answer:

d) 12 V

Explanation:

Due to the symmetry of the problem, the potential (relative to infinity) at the midpoint of the square, is the same for all charges, provided they be of the same magnitude and sign, and be located at one of the corners of the square.

We can apply the superposition principle (as the potential is linear with the charge) and calculating the total potential due to the 4 charges, just adding the potential due to any of  them:

V = V(Q₁) + V(Q₂) +V(Q₃) + V(Q₄) = 4* 3.0 V = 12. 0 V

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Answer:

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hope this helps

Explanation:

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2 years ago
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Leviafan [203]

Answer:

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6 0
2 years ago
a body of a mass 1kg suspended from a spring is found to stretch the spring by 10cm. (A) what is the spring constant? what is pe
Nikitich [7]

Answer:

(A) The spring constant is <u>98 N/m.</u>

(B) The period of oscillation is <u>0.635 s.</u>

Explanation:

Given:

Mass of the body is, m=1\ kg

Extension length of the spring is, x=10\ cm=0.1\ m

Now, let 'k' be the spring constant.

The force acting on the body is due to gravity only and is equal to its weight.

So, weight of the body is given as:

F_g=mg\\F_g=1\times 9.8\\F_g=9.8\ N

Now, we know that for a spring-mass system, the net force acting on the body is equal to the product of the spring constant and extension length. Therefore,

F_g=kx\\9.8=k(0.1)\\k=\frac{9.8}{0.1}=98\ N/m

Hence, the spring constant is 98 N/m.

(B)

Period of oscillation of a body of spring-mass system in SHM is given as:

T=2\pi\sqrt{\frac{m}{k}}

Plug in the given values and solve for period 'T'. This gives,

T=2\pi\sqrt{\frac{1}{98}}\\T=2\pi\times 0.101\\T=0.635\ s

Therefore, the period of oscillation is 0.635 s.

5 0
3 years ago
how much gravitational potential energy does a 5 kg rock have if is sitting on the edge of a cliff that is 10m high
docker41 [41]
Gpe =5 x 9.8 x 10 = .... Joules
8 0
3 years ago
Hoover Dam on the Colorado River is the highest dam in the United States at 221m, with a power output of 680 MW. The dam generat
DiKsa [7]

Answer:

The power in this flow is 9.56\times10^{8}\ W

Explanation:

Given that,

Distance = 221 m

Power output = 680 MW

Height =150 m

Average flow rate = 650 m³/s

Suppose we need to calculate the power in this flow in watt

We need to calculate the pressure

Using formula of pressure

Pressure=\rho g h

Where, \rho= density

h = height

g = acceleration due to gravity

Put the value into the formula

Pressure=1000\times9.8\times150

Pressure=1470000\ Nm^2

We need to calculate the power

Using formula of power

P=Pressure\times flow\ rate

Put the value into the formula

P=1470000\times650

P=9.56\times10^{8}\ W

Hence, The power in this flow is 9.56\times10^{8}\ W

5 0
2 years ago
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