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sergejj [24]
3 years ago
9

The potential (relative to infinity) at the midpoint of a square is 3.0 V when a point charge of +Q is located at one of the cor

ners of the square. What is the potential (relative to infinity) at the center when each of the other corners also contains a point charge of +Q?
a) 0 V
b) 3.0 V
c) 9.0 V
d) 12 V
Physics
1 answer:
Sveta_85 [38]3 years ago
4 0

Answer:

d) 12 V

Explanation:

Due to the symmetry of the problem, the potential (relative to infinity) at the midpoint of the square, is the same for all charges, provided they be of the same magnitude and sign, and be located at one of the corners of the square.

We can apply the superposition principle (as the potential is linear with the charge) and calculating the total potential due to the 4 charges, just adding the potential due to any of  them:

V = V(Q₁) + V(Q₂) +V(Q₃) + V(Q₄) = 4* 3.0 V = 12. 0 V

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Pani-rosa [81]

Answer:

Explanation:

given,

cyclist ride  6.2 km east and then 9.28 km in the direction of 27.27° west of north and then 7.99 km west.

vertical component = 9.28 cos∅

                                = 9.28 cos 27.27°

                                = 8.24 km

horizontal axis component = 9.28 sin ∅

                                             = 9.28 sin 27.27°

                                             = 4.5 km

distance of the final point from the origin

                            = 7.99 -(6.2-4.5)

                            = 6.29 km

displacement

d = \sqrt{6.29^2+8.24^2}

d = 10.37 km

b) tan \theta = \dfrac{6.29}{8.24}

θ = 37.36°

4 0
3 years ago
For a star with a parallax angle of 1/2 of an at arcsecond, what will be its distance in parsec?
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(1 parsec) is the distance at which an object has a parallax of 1 arcsecond. The distance is about 3.26 light years.

Another way to understand it is:  The distance from which the Earth's orbit appears 1 arcsecond across.

For a parallax angle of 1/2 arcsecond, the distance is <em>2 parsecs </em>(about 6.52 light years).

1 arcsecond is 1/3600 of a degree, 0.00028 degree.  

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Answer:

V = V_0 - (lamda)/(2pi(epsilon_0))*ln(R/r)

Explanation:

Attached is the full solution

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Isotopes of an element differ in their number of ?
Lera25 [3.4K]

neutrons

Explanation:

Isotopes of an element differ in their number of neutrons.

Isotopy is the existence of two or more atoms of the same element having the same atomic number but different mass numbers due to the differences in the  number of neutrons in their nucleus.

  • Isotopes of an element have the same electronic configuration.
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  • The mass of an atom is function of the protons and neutrons.

Learn more:

Isotope brainly.com/question/2593342

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4 0
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