2 cakes - Theresa's and Joe's
Theresa's cake had 6 pieces after she cut it. (2 times the size of Joe's pieces)
Joe's cake had 12 pieces after he cut it. (1/2 the size of Theresa's pieces)
We know that 8/12ths of ONE cake were eaten and that Joe ate 2 of his pieces.
We want to know how many pieces Theresa ate of her cake. Keeping in mind that her pieces are equal to 2 of Joe's pieces we can solve this question.
8/12 eaten total
if 2/12 by Joe
then 8-2 = 6, 6/12 by Theresa
(BUT: Theresa's pieces were twice the size of Joe's so we will divide by 2)
6/12 = 3/6
Answer: Theresa ate 3 pieces of her cake
That's not true because the GCF of 9 and 12 are both three and three is an odd number
Answer:
38.5 years old
Step-by-step explanation:
Let us represent Mrs.Kelly's age with the parameter (k). It is given that her brother is (15) years younger than her, thus his age is (k - 15). It is given that the sum of their ages is (62). Therefore one can form an equation with the given information and solve for the unknown.
(Mrs.Kelly's age) + (Brother) = (62)
Substitute,
(k) + (k - 15) = 62
Simplify,
k + k - 15 = 62
2k - 15 = 62
Inverse operations,
2k - 15 = 62
2k = 77
k = 38.5