Answer:
y = - 2x + 3
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = 
with (x₁, y₁ ) = (0, 3) and (x₂, y₂ ) = (1,1) ← 2 points on the line
m = 
= - 2
The line crosses the y- axis at (0, 3) ⇒ c = 3
y = - 2x + 3 ← equation of line
Hey there!
We know options. B and D aren't going to be your answer because they are way too big to be equivalent to 200
In order for you to find out which one is equivalent to 200 you have to calculate you late the options until you get to 200 and then you could do process of elimination!
It can't be A because 2/10 = 0.20 aka 20%
It can't be option. C because 10/20 = 0.50 aka 50%
So none of the above would be your answer
The correct answer would most likely be: 10√2
Good luck on your assignment and enjoy your day!
~LoveYourselfFirst:)
N = number of nights
M = number of meals
n = cost per night
m = cost per meal
T = total cost
Nn + Mm = T
They give us two scenarios :
1. N = 3 and M = 1 and T = 250
3n + 1m = 250
2. N = 3 and M = 6 and T = 330
3n + 6m = 330
Thus, we have a system of equations.
In the first equation, solve for m.
m = 250 - 3n
Now, plug this into the second equation and solve for n.
3n + 6m = 330
3n + 6(250 - 3n) = 330
3n + 1500 - 18n = 330
-15n = -1170
n = $78
Now, plug this back into our equation for m and solve.
m = 250 - 3n
m = 250 - 3(78)
m = 250 - 234
m = $16
Thus, it costs $78 per night and $16 per meal.
Answer:
s = 71 mph, and s+9 = f = 80 mph
Step-by-step explanation:
The distances the two busses travel add up to 604 mi.
Letting f be the faster speed and s the slower. Then f = s + 9 (mph).
Then (s + 9)(mph)(4 hr) + (s)(mph)(4 hr) = 604 mi. Solve this for s:
4s + 36 + 4s = 604 mi, or 8s = 568. Finally, s = 71 mph, and s+9 = f = 80 mph.
Step-by-step explanation:
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