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faust18 [17]
3 years ago
5

A rental company charges $15 plus $4 per hour to rent a bicycle. if margie does not want to spend more than $27 for her rental,

choose the inequality which represents how many hours she can rent the bicycle and not spend more than $27. interpret the solution.
Mathematics
1 answer:
Zepler [3.9K]3 years ago
6 0
4*X + 15 <= 274*X <= 12X <= 3 
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Express sin110 as ratio of acute angle
lesya [120]

Answer:

sin70°

Step-by-step explanation:

Given sin110° where 110° is an obtuse angle in the second quadrant.

The related acute angle in the first quadrant is 180° - 110° = 70°

Thus

sin110° = sin70°

8 0
3 years ago
The ratio of volume of a cone and a hemisphere of same base radius and height is?
aliya0001 [1]

Answer:

1/2

Step-by-step explanation:

Since it is given that the cone and the hemisphere have the same height, and since the height of a hemisphere would be equal to its radius, the cones height must also be equal to its base radius.

With this information we can use the respective volume formulas.

Hemisphere:  \frac{2}{3}πr^3

Cone:  \frac{1}{3}πhr^2

Since h (height) = r we can say the cone volume equals:

\frac{1}{3}πr^3

Now to find the ratio we divide the cone volume equation by the hemisphere volume equation

pi and r^3 cancels out from the division and we are left with

ratio = (1/3)/(2/3)

ratio = 1/2

7 0
3 years ago
Si el velocimetro de un auto marca un 25% mas que la verdadera velocidad y en este momento marca 100km/h entonces la velocidad v
GenaCL600 [577]

Answer:

True speed of the car is 87 km/h.

Step-by-step explanation:

Speed = 100 km/h

hike in speed = 25 %

Let the true speed is v.

v + 15% of v = 100 \\\\v + 0.15 v = 100 \\\\1.5 v = 100\\\\ v = 87  km/h

6 0
3 years ago
Chang drove 420 miles using 18 gallons of gas. At this rate, how many gallons of gas would he need to drive 357 miles?
qwelly [4]

Answer:

<h2>15.3 gallons</h2><h2 />

Step-by-step explanation:

ratio and proportion

<u>420 miles </u>   =   <u> 357 miles</u>

18 gallons          x gallons

420 (x) = 357 (18)

x = 6426 / 420

x = 15.3 gallons

4 0
3 years ago
Read 2 more answers
J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.
melamori03 [73]

Answer:

99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

Step-by-step explanation:

We are given that a random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $74.50 with a standard deviation of $17.25.

A random sample of 9 sales receipts for internet sales results in a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal quantity that will be used for constructing 99% confidence interval for true mean difference is given by;

                      P.Q.  =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }  ~ t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean for mail-order sales = $74.50

\bar X_2 = sample mean for internet sales = $84.40

s_1 = sample standard deviation for mail-order purchases = $17.25

s_2 = sample standard deviation for internet purchases = $21.25

n_1 = sample of sales receipts for mail-order purchases = 16

n_2 = sample of sales receipts for internet purchases = 9

Also,  s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }  =  \sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} } = 18.74

The true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is represented by (\mu_1-\mu_2).

Now, 99% confidence interval for (\mu_1-\mu_2) is given by;

             = (\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_)  \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}

Here, the critical value of t at 0.5% level of significance and 23 degrees of freedom is given as 2.807.

          = (74.50-84.40) \pm (2.807  \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})

          = [$-31.82 , $12.02]

Hence, 99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

5 0
3 years ago
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