<h3 />
The lac operon of E. coli contains genes involved in lactose metabolism. It's expressed only when lactose is present and glucose is absent.
<h3>How is the lac operon triggered by E. coli?</h3>
The lac operon of E. coli contains genes related to lactose metabolism. Only when lactose and glucose levels are low does it manifest symptoms. Two regulators that control the operon's "on" and "off" states in response to lactose and glucose concentrations are lac repressor and catabolite activator protein (CAP).
<h3>Why does E. coli prefer glucose to lactose?</h3>
Because it promotes quicker development than other sugars and is the first sugar to be consumed in sugar combinations, glucose is frequently the best carbon source for E. coli.
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Answer:
20.3%
Explanation:
Given that:
An AAbb strain is crossed to an aaBB strain
i.e.
AAbb × aaBB
gametes Ab aB
For F₁
generation;
If the resulting progeny are now self-crossed.
We know that the genetic distance between these two genes on the same chromosome is said to be 10 cM.
i.e. the recombinant gene = 10%; Hence, the parental gene will be (100 - 10)% = 90%
Ab × aB = Aa AB ab Bb
From above; the parental gene;
Ab and aB = 90% with each being 45%
i.e. Ab = 45% and aB = 45%
while the recombinants genes are:
AB and ab = 10%
i.e. AB = 5% and ab = 5%
Finally; the percentage of aaBB is = aB% × aB% × 100%
the percentage of aaBB is = 0.45 × 0.45 × 100%
the percentage of aaBB is = 20.25% ≅ 20.3%
It has given individuals with 1 of their most essential needs, a dependable supply of nourishment.
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.............................Correct.
Since the somatic cell count of a roundworm is four, the gamete count would be two. gamete count is half of somatic.
