Answer:
Step-by-step explanation:
¿Entre que números naturales consecutivos se encuentra cada raíz?
Bueno en este caso debes empezar por el 1 en adelante, pero solo sucede en números impares consecutivos. Solamente debes sumar 1,3,5,7,9,11,13,15,17,19 ..... en adelante, y en cada suma de cada sucesión encontraras un cuadrado. Ojo solo sumando en orden, tampoco sumarás 3+9, ya que te dará 12 y 12 No tiene raíz.
1+3=4,√4=2
4+5=9, √9=3
9+7=16, √16=4
16+9=25, √25=5
25+11=36, √36=6
36+13=49, √49=7
49+15=64, √64=8
64+17=81, √81=9
81+19=100, √100=10
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A SI CONSECUTIVAMENTE SIEMPRE OBTENDRÁS CADA RAÍZ
¿Entre que números naturales consecutivos se encuentra cada raíz?
R= En los número impares consecutivos, comenzando por el 1 en adelante.
The hypothenuse of a triangle 30, 60 or 90, is always two times the length of the short leg
Answer:
Step-by-step explanation:
As it is given that
Both Riley and Francesca commute to work.
And, the Riley takes 12 minutes more than as Francesca as Riley takes 36 minutes
So for determining how many minutes is required for Francesca to get to work we need
Let us assume the time taken by Francesca to get to work is x
So, the time taken by Riley is
And, Riley takes 36 minutes to get to work.
So, the equation would be
Answer:
b
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (- 1, 2) and (x₂, y₂ ) = (3, 1)
m = 
= - 
, thus
y = - x + c ← is the partial equation
To find c substitute either of the 2 points into the partial equation
Using (- 1, 2), then
2 = + c ⇒ c = 2 - = 
y = - x + ← in point- slope form
Multiply through by 4
4y = - x + 7 ( add x to both sides )
x + 4y = 7 → b
Answer:
y = x +1
Step-by-step explanation:
y= mx + b
where m is the slope and b is the y-intercept
m = (y2-y1)/ (x2-x1) = 2+4 / 3+3 = 6/6 = 1
from the point -slope equation we have
y-y1 = m* (x-x1)
y-3 = 1* ( x-2)
y= x -2+3
y= x +1
so the slope m=1 and the y-intercept b=1
