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Stels [109]
3 years ago
14

HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
7 0

Answer:

A

Step-by-step explanation:

It will always go down if you put more wait.

Can I have Brainliest

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If a polynomial function f(x) has roots 3+ V5 and -6, what must be a factor of f(x)?
Mkey [24]

Answer:

Step-by-step explanation:

Radicals and imaginary numbers ALWAYS come in pairs when it comes to factors of polynomials. This is the called the conjugate theorem. If we are given a solution/root/zero that is

x = 3 + √5, then its conjugate is x = 3 - √5. Going backwards from the solution to the factor, we utilize the Zero Product Property and get

(x - (3 - √5)) which simplifies to (x - 3 + √5). if you are looking for the conjugate of the given zero, the choice you want is the second one down.

5 0
3 years ago
PLEASE HELP ME SOLVE THIS<br><br> THANK U!!
V125BC [204]
Step 1) Draw a dashed line through the points (0,6) and (4,7). These two points are on the line y = (1/4)x+6. To find those points, you plug in x = 0 to get y = 6. Similarly, plug in x = 4 to get y = 7. The dashed line indicates that none of the points on this line are part of the solution set.

Step 2) Draw a dashed line through (0,-1) and (1,1). These two points are on the line y = 2x-1. They are found in a similar fashion as done in step 1. 

Step 3) Shade the region that is above both dashed lines. We shade above because of the "greater than" sign. This is shown in the attached image I am providing below. The red shaded region represents all of the possible points that are the solution set. Once again, any point on the dashed line is not in the solution set. 

5 0
3 years ago
An experiment was performed on a 2kg block. Forces 5, 10, and 15 Newton's respectively were applied to the block for 5 seconds.
babymother [125]

Answer:

B) The final acceleration will triple between the first and third trial.

7 0
3 years ago
Determine if the ordered pair is a solution of the equation.
lakkis [162]
A. True
y=3x
3=3(1)
3=3
7 0
3 years ago
Solve for v when B=3 x v/h
forsale [732]

B=3\cdot\dfrac{v}{h}\qquad|\cdot h\neq0\\\\Bh=3v\qquad|:3\\\\\boxed{v=\dfrac{Bh}{3}}

6 0
3 years ago
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