Answer:
For, "x" greater than 34, the perimeter of the picture frame greater than 152 inches
Solution:
Let "x" be the width of the frame
Given that, The length of a picture frame is 8 inches more than the width
Therefore,
Length = width + 8
Length = x + 8
The perimeter of rectangle is given by formula:
Perimeter = 2(length + width)
Substituting the values we get,
Perimeter = 2(x + 8 + x)
Perimeter = 2(2x + 8)
Perimeter = 4x + 16
The perimeter of the picture frame greater than 152 inches
Perimeter > 152
Therefore, for, "x" greater than 34, the perimeter of the picture frame greater than 152 inches
Step-by-step explanation:
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having just turned 16 years old, your friend has their mind set on buying a new car by the time they turn 20 years old
Answer:
= 30,550 rupee owed
Step-by-step explanation:
yr1 = 50000 x 0.10^1 = 5000
5000 - 10000 = 5000 credit from debt.
yr 2 = 50000 x 1.10^2 = 500 debit from debt = 5000-15000= 10,000 credit from debt
yr 3 = 50000 x 1.10^3 = 50 debit from debt
5000 + 500 = 15000 where 50,000 owed initially and yr1 and yr 2 paid in full interest of 5500 and we deduct this from his payment = 25000-5500 =
19500 paid of initial and nothing owed on interest.
50000-19500= 30,500 rupees owed + 50 rupee interest.
= 30,550 rupee owed
Answer: Your answers ×=5 !
Answer:
Step-by-step explanation:
Area of the rectangular piece A = xy
x is the length
y is the width
Perimeter =2x+2y
Given
Perimeter = 3044yds
3044 = 2x+2y
1522 = x+y
x = 1522-y
Substitute into the formula for area
A = xy
A = (1522-y)y
A = 1522y-y²
To maximize the area, dA/dy must be zero
dA/dy = 1522-2y
0 = 1522-2y
2y = 1522
y = 1522/2
y = 761
Since x+y = 1522
X+761 = 1522
X = 761
Dimension is 761yd by 761yd
Area = 761×761 = 579121yd²