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3 years ago

Solve for the unknown by using the additive inverse. Type the FULL answer in the box, without using any spaces (ex., X=5).

Mathematics

1 answer:

svlad2 [7]3 years ago

8 0

Answer: Y=-1

Explanation: 2y-3=y-4 (add three on both sides)
2y=y-1 (subtract y on both sides)
y=-1

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3 years ago

Three times the sum of 4 and a number is twice the<br> number. Find the number.

zavuch27 [327]

Step-by-step explanation:

let number be x

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3 years ago

-3p-4<6 help me please never done these before and teacher isn’t at school to ask!!!

tia_tia [17]

Answer:

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Step-by-step explanation:

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1 year ago

2.(08.04 MC)

Anestetic [448]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Activity 2. Find the equation of the line using Two-Point form,

jasenka [17]

Answer:

1) equation of line is: y-3=0

2) equation of line is: $\mathbf{y-3=-\frac{1}{2}(x-4)}$

3) equation of line is: $\mathbf{y+3=-\frac{4}{3}(x-3}$

4) equation of line is: $\mathbf{y-2=-2(x-2)}$

Step-by-step explanation:

We need to find the equation of the line using Two-Point form.

The general equation of two-point form is: $y-y_1=m(x-x_1)$ where m is slope.

The formula used to calculate slope is: $Slope=\frac{y_2-y_1}{x_2-x_1}$

1. (1,3) and (-2,3)

First finding slope

We have: $x_1=1, y_1=3, x_2=-2, y_2=3$

$Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{3-3}{-2-1}\\Slope=\frac{0}{-3}\\Slope=0\\$

So, equation of line will be:

Using slope m=0 and point (1,3)

$y-y_1=m(x-x_1)\\y-3=0(x-1)\\y-3=0\\$

So, equation of line is: y-3=0

2. (4,3) and (6,2)

First finding slope

We have: $x_1=4, y_1=3, x_2=6, y_2=2$

$Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{2-3}{6-4}\\Slope=\frac{-1}{2}\\$

So, equation of line will be:

Using slope m= $\frac{-1}{2}$ and point (4,3)

$y-y_1=m(x-x_1)\\y-3=\frac{-1}{2}(x-4)\\y-3=-\frac{1}{2}(x-4)$

So, equation of line is: $\mathbf{y-3=-\frac{1}{2}(x-4)}$

3) (3,-3) and (0,1)

First finding slope

We have: $x_1=3, y_1=-3, x_2=0, y_2=1$

$Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{1-(-3)}{0-3}\\Slope=\frac{1+3}{-3}\\Slope=-\frac{4}{3}\\$

So, equation of line will be:

Using slope m= $-\frac{4}{3}$ and point (3,-3)

$y-y_1=m(x-x_1)\\y-(-3)=-\frac{4}{3}(x-3)\\y+3=-\frac{4}{3}(x-3)\\$

So, equation of line is: $\mathbf{y+3=-\frac{4}{3}(x-3)}$

4) (2,2) and (4,-2)

First finding slope

We have: $x_1=2, y_1=2, x_2=4, y_2=-2$

$Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{-2-2}{4-2}\\Slope=\frac{-4}{2}\\Slope=-2\\$

So, equation of line will be:

Using slope m=-2 and point (2,2)

$y-y_1=-2(x-x_1)\\y-2=-2(x-2)\\$

So, equation of line is: $\mathbf{y-2=-2(x-2)}$

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3 years ago