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Vanyuwa [196]
3 years ago
11

Solve for the unknown by using the additive inverse. Type the FULL answer in the box, without using any spaces (ex., X=5).

Mathematics
1 answer:
svlad2 [7]3 years ago
8 0
Answer: Y=-1

Explanation: 2y-3=y-4 (add three on both sides)
2y=y-1 (subtract y on both sides)
y=-1
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Three times the sum of 4 and a number is twice the<br> number. Find the number.
zavuch27 [327]

Step-by-step explanation:

let number be x

3(4+x)=2x

12 + 3x = 2x

12 = 2x - 3x

12 = -x

x= -12

3 0
3 years ago
-3p-4&lt;6 help me please never done these before and teacher isn’t at school to ask!!!
tia_tia [17]

Answer:

p>-1/3

Step-by-step explanation:

-3p-4<6

+4 +4

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-3p<10

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7 0
1 year ago
2.(08.04 MC)
Anestetic [448]

Answer:

353kg

Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
Activity 2. Find the equation of the line using Two-Point form,
jasenka [17]

Answer:

1) equation of line is: y-3=0

2) equation of line is: \mathbf{y-3=-\frac{1}{2}(x-4)}

3) equation of line is: \mathbf{y+3=-\frac{4}{3}(x-3}

4) equation of line is: \mathbf{y-2=-2(x-2)}

Step-by-step explanation:

We need to find the equation of the line using Two-Point form.

The general equation of two-point form is: y-y_1=m(x-x_1) where m is slope.

The formula used to calculate slope is: Slope=\frac{y_2-y_1}{x_2-x_1}

1. (1,3) and (-2,3)

First finding slope

We have: x_1=1, y_1=3, x_2=-2, y_2=3

Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{3-3}{-2-1}\\Slope=\frac{0}{-3}\\Slope=0\\

So, equation of line will be:

Using slope m=0 and point (1,3)

y-y_1=m(x-x_1)\\y-3=0(x-1)\\y-3=0\\

So, equation of line is: y-3=0

2. (4,3) and (6,2)

First finding slope

We have:x_1=4, y_1=3, x_2=6, y_2=2

Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{2-3}{6-4}\\Slope=\frac{-1}{2}\\

So, equation of line will be:

Using slope m=\frac{-1}{2} and point (4,3)

y-y_1=m(x-x_1)\\y-3=\frac{-1}{2}(x-4)\\y-3=-\frac{1}{2}(x-4)

So, equation of line is: \mathbf{y-3=-\frac{1}{2}(x-4)}

3) (3,-3) and (0,1)

First finding slope

We have: x_1=3, y_1=-3, x_2=0, y_2=1

Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{1-(-3)}{0-3}\\Slope=\frac{1+3}{-3}\\Slope=-\frac{4}{3}\\

So, equation of line will be:

Using slope m=-\frac{4}{3} and point (3,-3)

y-y_1=m(x-x_1)\\y-(-3)=-\frac{4}{3}(x-3)\\y+3=-\frac{4}{3}(x-3)\\

So, equation of line is: \mathbf{y+3=-\frac{4}{3}(x-3)}

4) (2,2) and (4,-2)

First finding slope

We have: x_1=2, y_1=2, x_2=4, y_2=-2

Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{-2-2}{4-2}\\Slope=\frac{-4}{2}\\Slope=-2\\

So, equation of line will be:

Using slope m=-2 and point (2,2)

y-y_1=-2(x-x_1)\\y-2=-2(x-2)\\

So, equation of line is: \mathbf{y-2=-2(x-2)}

3 0
3 years ago
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