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Vanyuwa [196]
3 years ago
11

Solve for the unknown by using the additive inverse. Type the FULL answer in the box, without using any spaces (ex., X=5).

Mathematics
1 answer:
svlad2 [7]3 years ago
8 0
Answer: Y=-1

Explanation: 2y-3=y-4 (add three on both sides)
2y=y-1 (subtract y on both sides)
y=-1
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Write the equation of the line from the graph<br> (show your work pls)
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It is just y=-4 since the line is horizontal
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Which function is represented by the values in the table below?
shusha [124]
D y=2x + 1
i think but i hope that helps
3 0
3 years ago
How to solve this question?
bagirrra123 [75]

Answer:

-11.

Step-by-step explanation:

f(x) = √(3 - 2x),   x ≤ 3/2

let y = √(3 - 2x)

y^2 = 3 - 2x

2x = 3 - y^2

x = (3 - y^2)/2

So f-1(x) = (3 - x^2)/2  

f-1(x) = (3 - 5^2) / 2 = -11.

7 0
2 years ago
4 Suppose you throw a dart at a circular target of radius 10 inches. Assuming that you hit the target and that the coordinates o
Lady bird [3.3K]

Answer:

0.04,0.25.0.52

Step-by-step explanation:

Given that you throw a dart at a circular target of radius 10 inches.

Assuming that you hit the target and that the coordinates of the outcomes are chosen at random,

probability that the dart falls

(a) within 2 inches of the center

Here favourable region has area of a circle with radius 2 inches and sample space has area of 10 inches

Prob = \frac{\pi *2^2}{\pi *10^2} \\\\=\frac{1}{25}

(b) within 2 inches of the rim.

For within two inches from the rim we have to select area of the ring i.e. area of big circle with 10 inches - area of smaller circle with 10-2 inches

Prob= \frac{\pi * *8^2}{\pi*10^2} \\=0.64

c) within I quadrant

area of I quadrant / area of circle=0.25

d) within I quadrant and within 2 inches of the rim

= I quadrant area + 2 inches ring area - common area

= \frac{\pi*10^2/4 + pi*(10^2-8^2) - \pi(10^2-8^2)/4}{\pi*10^2} \\=\frac{25+36-9}{100} \\=0.52

3 0
3 years ago
Practice: Write and Evaluate Expressions - Practice --- Level
Ray Of Light [21]
1/2x(25-7). Difference means to subtract. And then just multiply by 1/2 since it is asking for half.
8 0
2 years ago
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