Question

How many moles of KBr are present in 500 ml of a 0.8 M KBr solution?

Answer 1

Answer:

2) 0.4 mol

Explanation:

Step 1: Given data

• Volume of the solution (V): 500 mL

• Molar concentration of the solution (M): 0.8 M = 0.8 mol/L

Step 2: Convert "V" to L

We will use the conversion factor 1 L = 1000 mL.

500 mL × 1 L/1000 mL = 0.500 L

Step 3: Calculate the moles of KBr (solute)

The molarity is the quotient between the moles of solute (n) and the liters of solution.

M = n/V

n = M × V

n = 0.8 mol/L × 0.500 L = 0.4 mol