How water deposits soil sediment and rock

1 answer:

n200080 [17]3 years ago

8 0

A river can only carry a load if it has adequate energy. When the energy drops below a certain level, therefore, the load is dropped. In the Thalweg (the line of fastest flow), more load is carried, and this is also where the erosion occurs, adding more load. On the inside of a meander, for example, since the Thalweg is on the outside, the velocity on the inside is very low, and so deposition occurs. On the very inside, water merely trickles past. This is incapable of transporting load, so it deposits it until it is able to carry all of it.

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What is an electrolytic cell?

Verizon [17]

Answer:

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Explanation:

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Be sure to answer all parts. Sulfur dioxide is released in the combustion of coal. Scrubbers use lime slurries of calcium hydrox

scoray [572]

Answer: The balanced chemical equation is written below and $\Delta S^o$ for the reaction is -160.6 J/K

Explanation:

When calcium hydroxide reacts with sulfur dioxide, it leads to the formation of calcium sulfate and water molecule.

The chemical equation for the reaction of calcium hydroxide and sulfur dioxide follows:

$Ca(OH)_2(s)+SO_2(g)\rightarrow CaSO_3(s)+H_2O(l)$

To calculate the entropy change of the reaction, we use the equation:

$\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{products}]-\sum [n\times \Delta S^o_{reactants}]$

For the given reaction:

$\Delta S^o_{rxn}=[(1\times \Delta S^o_{CaSO_3(s)})+(1\times \Delta S^o_{H_2O(l)})]-[(1\times \Delta S^o_{Ca(OH)_2(s)})+(1\times \Delta S^o_{SO_2(g)})]$

Taking the standard entropy change values:

$\Delta S^o_{CaSO_3(s)}=101.4Jmol^{-1}K^{-1}\\\Delta S^o_{H_2O(l)}=69.9Jmol^{-1}K^{-1}\\\Delta S^o_{Ca(OH)_2(s)}=83.4Jmol^{-1}K^{-1}\\\Delta S^o_{SO_2(g)}=248.5Jmol^{-1}K^{-1}$