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3 years ago

How water deposits soil sediment and rock

1 answer:

n200080 [17]3 years ago

8 0

A river can only carry a load if it has adequate energy. When the energy drops below a certain level, therefore, the load is dropped. In the Thalweg (the line of fastest flow), more load is carried, and this is also where the erosion occurs, adding more load. On the inside of a meander, for example, since the Thalweg is on the outside, the velocity on the inside is very low, and so deposition occurs. On the very inside, water merely trickles past. This is incapable of transporting load, so it deposits it until it is able to carry all of it.

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An atom of potassium loses one electron. what does it become a negative potassium, positive potassium

STALIN [3.7K]

Yes, K+ is a potassium ion, and Mg2+ is a magnesium ion. But However, when non-metallic elements gain the electrons to form anions, Yes the end of their name is changed to “-ide.” and yes the example, a fluorine atom gains one electron to become a yes fluoride ion (F-) sooo yeessyes

5 0

3 years ago

The combustion of carbohydrates and the combustion of fats are both exothermic processes, yet the combustion of carbohydrates is

saveliy_v [14]

Explanation:

Combustion of a compound is the reaction with oxygen , hence , the process of combustion is an oxidation reaction.

The carbohydrates contain more amount of oxygen as compared to the fats ,

Hence ,

carbohydrates , have a lot of oxygen contents , are are already partially oxidized , but fats have lower oxygen content .

Therefore ,

The partially oxidized carbohydrates are very difficult to oxidized in comparison to fats .

4 0

3 years ago

The Michaelis constant for pancreatic lipase is 5 mM. At 60 C, lipase is subject to deactivation with a half-life of 8 min. Fat

Dmitriy789 [7]

Explanation:

According to the given data, we will calculate the following.

Half life of lipase $t_{1/2}$ = 8 min x 60 s/min

= 480 s

Rate constant for first order reaction is as follows.

$k_{d} = \frac{0.6932}{480}$

= $1.44 \times 10^{-3}s^{-1}
$

Initial fat concentration $S_{o}$ = 45 $mol/m^{3}$

= 45 mmol/L

Rate of hydrolysis $V_m_{o}$ = 0.07 mmol/L/s

Conversion X = 0.80

Final concentration (S) = $S_{o} (1 - X)$

= 45 (1 - 0.80)

= 9 $mol/m^{3}$

or, = 9 mmol/L

It is given that $K_{m}$ = 5mmol/L

Therefore, time taken will be calculated as follows.

t = $-\frac{1}{K_{d}}ln[1 - \frac{K_{d}}{V}{K_{M} ln (\frac{S_{o}}{S}) + (S_{o} - S)]$

Now, putting the given values into the above formula as follows.

t = $-\frac{1}{K_{d}}ln[1 - \frac{K_{d}}{V}{K_{M} ln (\frac{S_{o}}{S}) + (S_{o} - S)]$

= $-\frac{1}{1.44 \times 10^{-3}s^{-1}}ln[1 - \frac{1.44 \times 10^{-3}s^{-1}}{0.07 mmol/L/s
}{K_{M} ln (\frac{45 mmol/L
}{9 mmol/L
}) + (45 mmol/L - 9 mmol/L
)]$

= $1642.83 s \times \frac{1 min}{60 sec}$

= 27.38 min

Therefore, we can conclude that time taken by the enzyme to hydrolyse 80% of the fat present is 27.38 min.

6 0

3 years ago

Animals use oxygen in the process of blank and emit CO2 as a byproduct.

Temka [501]

Answer:

Respiration

Explanation:

The act of breathing, simple as that!

Hope this helped!!

4 0

2 years ago

A different student is given a 10.0g sample labeled CaBr2 that may contain an inert (nonreacting) impurity. Identify a quantity

grandymaker [24]

Answer:

Mass of Ca in sample, Mass of Br in sample, Number of moles of Ca in sample, Number of moles of Br in sample, Mass or moles of element other than Ca or Br in sample

Explanation:

The AP Classroom will not count your answer to this question as correct unless it includes at least one of the answers listed above. If you say that theanswer to this question is density, it will be marked as incorrect, I found that out the hard way when I used the answers that brainly gave me.

Good luck,

I applaud you for using the sources avalible to you, which is /definetly not/ cheeting.

8 0

3 years ago